2000$ is a good price for brake bitcoin transaction

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Maybe I'm stupid, but the first example give me private key:
115792089237316195423570985008687907851824985096824206522838950949005526276248
in second example i have your right key:
1012579182250697859766212192512635217927
PS. I don't know how to calculate it

hexan/bD
you are not stupid. this is true:
we have two differents pubkey - it is problem of curve.:
r1=91569536891656778098714370566123400538808691962301036137348069575478543413371
s1=21986343255696161951638838250895082624842596755182648655691313830200114210986
z1=6438777035962518887320975299969341061899935085590046638463194556599680845483
k1= 5853058856940450056452093598338931896
result = 115792089237316195423570985008687907851824985096824206522838950949005526276248
which n- result = 1012579182250697859766212192512635218089
and:
r1=91569536891656778098714370566123400538808691962301036137348069575478543413371
s1=n - 21986343255696161951638838250895082624842596755182648655691313830200114210986
z1=6438777035962518887320975299969341061899935085590046638463194556599680845483
k1= 5853058856940450056452093598338931896
result: 1012579182250697859766212192512635217927
and this is problem -> any explanation?