Post
Topic
Board Bitcoin Discussion
Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
by
bestie1549
on 28/09/2023, 13:45:55 UTC
I have made a new discovery today, ( at least for me is new). You all know about lambda right?  Here :
5363ad4cc05c30e0a5261c028812645a122e22ea20816678df02967c1b23bd72

Multiplying any point by lambda will *metamorphose our x but not our y coordinates. I just realized if we take for example :
04bcace2e99da01887ab0102b696902325872844067f15e98da7bba04400b88fcb483ada7726a3c 4655da4fbfc0e1108a8fd17b448a68554199c47d08ffb10d4b8

04c994b69768832bcbff5e9ab39ae8d1d3763bbf1e531bed98fe51de5ee84f50fb483ada7726a3c 4655da4fbfc0e1108a8fd17b448a68554199c47d08ffb10d4b8

0479be667ef9dcbbac55a06295ce870b07029bfcdb2dce28d959f2815b16f81798483ada7726a3c 4655da4fbfc0e1108a8fd17b448a68554199c47d08ffb10d4b8

And dividing all three keys above by 2, will give us :
041b7b24bfec17f17cfad4ed5d26f3ba3f2ecde9516100d16dbfa3986c27223893c0c686408d517 dfd67c2367651380d00d126e4229631fd03f8ff35eef1a61e3c

04e484db4013e80e83052b1267603def814791291a8a098469934ed0bc5f7e2739c0c686408d517 dfd67c2367651380d00d126e4229631fd03f8ff35eef1a61e3c

0400000000000000000000003b78ce563f89a0ed9414f5aa28ad0d96d6795f9c63c0c686408d517 dfd67c2367651380d00d126e4229631fd03f8ff35eef1a61e3c

If we divide the keys above by any number, all their y coordinates will be identical, EC is like a giant web of interconnected triangles, by any chance is there any EC calculation which only y coordinates are used for an operation?


* I was reminded of Nevermore in dota. 🙃



Since I was nominated as the master mathematician, I invented this number  1073741824, there should be that many puzzle #66 identical addresses in 66 bit range?  Or maybe there are only 4 identical addresses?


if there are 4 identical addresses but our targets are the first 10 characters of puzzle 66, then there are 1073741824 addresses having similar first 10 characters within the 66 bit range

but we need to also note that if there are 4 identical addresses within the 66 bit range then our chances of hitting 1 should be 9223372036854775808 which still falls within 63 bit range which defnitely won't be an easy task to fin in any way because that is about 58 years on my 4090.

we need a better algorithm