subtract G 99 times from target, you will have 100 keys in total, then divide them all by 100, one of the results will definitely be the target/100. Then come here ask me what's next. But first I would need to test your script to see if it does what I said.😉
Hello, is this what you need?
import secp256k1 as ice
import bitcoin
target= "03633cbe3ec02b9401c5effa144c5b4d22f87940259634858fc7e59b1c09937852"
print("Target:", target)
Target_upub= ice.pub2upub(target)
for i in range (100):
A= ice.scalar_multiplication(i)
B= ice.point_subtraction(Target_upub, A)
C= ice.to_cpub(B.hex())
D= bitcoin.divide(C, 100)
data = open("S-1.txt","a")
data.write(str(i)+" = "+str(C)+"\n")
data.close()
data = open("D-1.txt","a")
data.write(str(i)+" = "+str(D)+"\n")
data.close()