Post
Topic
Board Bitcoin Discussion
Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
by
nomachine
on 25/11/2023, 09:19:11 UTC

Code:
import secp256k1 as ice
import random

print("scaning pub 03...")

target = "13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so"

start= 50000000000000000000
end=   70000000000000000000
while True:
    
    A0 = random.randint(start, end)
    A1 = ice.scalar_multiplication(A0)
    B0 = ice.to_cpub(A1.hex())
    
    if B0.startswith("03"):
        A2 = ice.pubkey_to_address(0,1, A1)
        print(A2)
        if target in A2:
            print("venga rata")
            data = open("Win.txt","a")
            data.write(str(A0)+" = "+A2+"\n")
            data.close()

Same script, but with concurrent.futures.


Code:
import concurrent.futures
import sys
import os
import time
import secp256k1 as ice
import random
import multiprocessing


os.system("clear");t = time.ctime();sys.stdout.write(f"\033[?25l")
sys.stdout.write(f"\033[01;33m[+] {t}\n")

def generate_key():
    start = 36893488147419103231
    end = 73786976294838206463
   
    A0 = random.randint(start, end)
    A1 = ice.scalar_multiplication(A0)
    B0 = ice.to_cpub(A1.hex())
   
    if B0.startswith("03"):
        A2 = ice.pubkey_to_address(0, 1, A1)
        message = "[+] {}".format(A2);messages = [];messages.append(message);output = ''.join(messages) + "\r";sys.stdout.write(output);sys.stdout.flush()
        return A0, A2
    else:
        return None, None

def main():
    target = "13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so"
   
    num_cores = multiprocessing.cpu_count()
   
    with concurrent.futures.ProcessPoolExecutor(max_workers=num_cores) as executor:
        while True:
            futures = [executor.submit(generate_key) for _ in range(num_cores)]
           
            for future in concurrent.futures.as_completed(futures):
                A0, A2 = future.result()
               
                if A2 and target in A2:
                    print("venga rata")
                    with open("Win.txt", "a") as data:
                        data.write(f"{A0} = {A2}\n")
                    break

if __name__ == "__main__":
    main()

You can imagine how this works on a 128 Core machine Grin

I use Python for testing or when speed is not required, C is better when it comes to speed, I am currently working on a method that allows you to find a key in bit30 in less than 10 seconds, really this part is not the curious one, the curious thing My script has a speed of 2048keys/s, how does it manage to find a key in that range in such a short time with that speed? There is a mathematical trick involved in it, I'm starting to write it in C, to focus on the puzzle 130, once I finish it, if this does not pose a security risk for bitcoin I will make it free.

those scripts (both) don't work as expected on my side. I tested with puzzle 30, even with 15 which should be cracked in fractions of seconds.

Puzzle 15
address = 1QCbW9HWnwQWiQqVo5exhAnmfqKRrCRsvW
start = 16384
end = 32768

Puzzle 30
address = 1LHtnpd8nU5VHEMkG2TMYYNUjjLc992bps
start = 536870912
end = 1073741824

no hit at all

You have to change   if B0.startswith("03"):   to    if B0.startswith("02"):
It might get better Wink