Post
Topic
Board Bitcoin Discussion
Re: Did you already break the Elliptic Curve, Satoshi, you there?
by
Legends_Never_Die
on 18/01/2024, 22:44:59 UTC
The question is, how are you going to determine 0 or 1s?
Anyways, before you break the grounds any further, you might wanna try this "earth shattering" script: 😉

Code:
from sympy import mod_inverse
import secp256k1 as ice
pub=ice.pub2upub('Here Compressed Public Key')
N=0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25E8CD0364141

k=mod_inverse(2,N)
neg1=ice.point_negation(ice.scalar_multiplication(1))


def ters(Qx,Scalar):
     ScalarBin = str(bin(Scalar))[2:]
     le=len(ScalarBin)
     for i in range (1,le+1):
        if ScalarBin[le-i] == "0":
            Qx=ice.point_multiplication(k,Qx)
        else:
            Qx=ice.point_addition(Qx,neg1)
            Qx=ice.point_multiplication(k,Qx)
     return ice.point_to_cpub(Qx)


for x in range(1,65536):
         f= (ters(pub,x))
         data= open(“halfpub.txt”,”a”)
         data.write(f+”\n”)
         data.close()
Code was first seen posted by @lordfrs, later modified by @mcdouglasx

Believe it or not, I have been where you are now, the difference is that I never created a github page to share incorrect code, your code has a few flaws, it's not even an algorithm, however the script I just shared is one.

One thing you have completely ignored is the fact that we can not multiply a point by another point, yet you base your research on that possibility.