i do some Experiment, trial and error for 66 bit
Let's say i take one 66 bit address for practice
000000000000000000000000000000000000000000000002be7989dd1a1a63ad | Hash 160 20cb77af1a425c5e74483d9b30cf950911a090de | 13zQNJwpREZogcPSkNJmYQzZ9HZQZS48Hx [TARGET]
result scan :
000000000000000000000000000000000000000000000002b809677889fb1078 | Hash 160 20cb78b594b77cf97259be5cc414f0a49f1bde81 | 13zQNb5x4P7vCjag18rZKCVHkBcqtddaLS | 102.92 sec | 136.0 keys/sec |
00000000000000000000000000000000000000000000000285a7e79fd01fc2a4 | Hash 160 20cbc445f68147eb89314c6710de2a7c5fc2e0fb | 13zQj6btR6awFjac835xsvDqeCtVyioiiW | 112.67 sec | 124.9 keys/sec |
000000000000000000000000000000000000000000000002757de2916bb72c92 | Hash 160 20cbc889d5186984e2189dd818e67d990f992459 | 13zQkFk3v2WXrhLVVhP2NKM1JT4Gbd6VoY | 153.39 sec | 110.4 keys/sec |
000000000000000000000000000000000000000000000002a6bdd8aaca2a5a56 | Hash 160 20cbb6398c3a2a9ad13eec60d2ffd84ed113d96d | 13zQfHTEd9EZncjXmiKMoZV7SqSZP39myL | 159.93 sec | 100.8 keys/sec |
I'm very grateful the result seem make some chance to hit the targeted and correct key
000000000000000000000000000000000000000000000002b809677889fb1078 | Hash 160 20cb78b594b77cf97259be5cc414f0a49f1bde81 | 13zQNb5x4P7vCjag18rZKCVHkBcqtddaLS | 102.92 sec | 136.0 keys/sec |
i make some checkpoint rules and check if at least 10 addresses have similarity in hash160 derived from private key.
What result are you talking about? I'm sorry if I can't see the wood for the trees, but I see absolutely nothing here that can be helpful in any way that relates to the topic of finding the puzzle. I see you have defined a target and I see you have listed four private keys and the corresponding addresses. There is no relation between them, how could there be, it wouldn't make any sense.
So what exactly did you find out or what makes you think that you're on the right track? Please don't misunderstand me, but I only see random data here without any relation to anything.