Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
if someone found 66 PK, can share with me, for withdraw, i know secure way to transfer, other you have seen above test, and definatly, slowly slowly lot of people would have 66 PK, but no one take step for attempt withdraw 
For a drowning person, even a straw is a great support. I will definitely contact you.When everything is dependent on fate, it's best that we only utilize this code. There's no need for undue force with the computer, no burden on the machine, no excessive worry about electricity costs, and most importantly, without any concern for double spending.
2^129 - 2^130 | PUB : 0383af736b4eefaa2f697e63b4530129ff34ff945be353ee498b0473238ea91ef4 | PVK : 0x2264f44bd23a25b4a5b8390e650cf9cae
2^134 - 2^135 | PUB : 03a987392d57dd82a9ee630f99a75b3925ca5417869bbdfc76b6f59997e558ee73 | PVK : 0x7a5330f4174f496ca6c4364888e9aef5db
2^139 - 2^140 | PUB : 0389d6d9b49a09988a70238b4c79639ef2881c686134075a485843e4814e36320d | PVK : 0xdffa0bf08d3584c46a48904da5df25016af
2^144 - 2^145 | PUB : 0226d47bfd7e231e9c123683137bf0f34522c03a8604fee9a9f626f0334daf9c0b | PVK : 0x167b8d6bec4db640ca2560f120f0a072bf658
2^149 - 2^150 | PUB : 0363abdd6ae3bc62c6ccf3d34d22b44d90f710fa99931d566a6a8c0da68acca933 | PVK : 0x3e1954a5af437841b085ba454c8b9e1149268a
2^154 - 2^155 | PUB : 035bebccb841e7b812fcfbc5fe86d9f9549e68d3d3da1bffd613e8a3960ca26ddc | PVK : 0x7a7179d2027c342b336fb8fd92347d50d937d1e
2^159 - 2^160 | PUB : 022cc56adb8c5385aefbb3cd38dfc2294560c4f73ad4562f68916535d6ab8ebf66 | PVK : 0xc09735b95a670ac005324cb8ddcf3576df7b3f1e
Code:
from bit import *
import random
L = [
'03633cbe3ec02b9401c5effa144c5b4d22f87940259634858fc7e59b1c09937852',
'02145d2611c823a396ef6712ce0f712f09b9b4f3135e3e0aa3230fb9b6d08d1e16',
'031f6a332d3c5c4f2de2378c012f429cd109ba07d69690c6c701b6bb87860d6640',
'03afdda497369e219a2c1c369954a930e4d3740968e5e4352475bcffce3140dae5',
'03137807790ea7dc6e97901c2bc87411f45ed74a5629315c4e4b03a0a102250c49',
'035cd1854cae45391ca4ec428cc7e6c7d9984424b954209a8eea197b9e364c05f6',
'02e0a8b039282faf6fe0fd769cfbc4b6b4cf8758ba68220eac420e32b91ddfa673'
]
while True:
seed = random.getrandbits(161)
random.seed(seed)
for exp in range(129, 164, 5):
a = random.randrange(2**exp, 2**(exp+1))
pk = Key.from_int(a)
key = Key.from_int(a)
pub = pk._pk.public_key.format(compressed=True)
addrpub = pub.hex()
if addrpub in L:
print('================found=====================\n')
f=open(u"Key_Found.txt","a")
f.write("Seed : " + str(seed) + "\n")
f.write("Prvk : " + hex(a) + "\n")
f.close()
input('================Exit=====================\n')
exit()
#if addrpub.startswith('03633cbe3') or addrpub.startswith('02145d26') or addrpub.startswith('031f6a33') or addrpub.startswith('03afdda4') or addrpub.startswith('03137807') or addrpub.startswith('035cd185') or addrpub.startswith('02e0a8b0'):
print(f"2^{exp} - 2^{exp+1} | PUB : {addrpub} | PVK : {hex(a)}", end = '\n')
import random
L = [
'03633cbe3ec02b9401c5effa144c5b4d22f87940259634858fc7e59b1c09937852',
'02145d2611c823a396ef6712ce0f712f09b9b4f3135e3e0aa3230fb9b6d08d1e16',
'031f6a332d3c5c4f2de2378c012f429cd109ba07d69690c6c701b6bb87860d6640',
'03afdda497369e219a2c1c369954a930e4d3740968e5e4352475bcffce3140dae5',
'03137807790ea7dc6e97901c2bc87411f45ed74a5629315c4e4b03a0a102250c49',
'035cd1854cae45391ca4ec428cc7e6c7d9984424b954209a8eea197b9e364c05f6',
'02e0a8b039282faf6fe0fd769cfbc4b6b4cf8758ba68220eac420e32b91ddfa673'
]
while True:
seed = random.getrandbits(161)
random.seed(seed)
for exp in range(129, 164, 5):
a = random.randrange(2**exp, 2**(exp+1))
pk = Key.from_int(a)
key = Key.from_int(a)
pub = pk._pk.public_key.format(compressed=True)
addrpub = pub.hex()
if addrpub in L:
print('================found=====================\n')
f=open(u"Key_Found.txt","a")
f.write("Seed : " + str(seed) + "\n")
f.write("Prvk : " + hex(a) + "\n")
f.close()
input('================Exit=====================\n')
exit()
#if addrpub.startswith('03633cbe3') or addrpub.startswith('02145d26') or addrpub.startswith('031f6a33') or addrpub.startswith('03afdda4') or addrpub.startswith('03137807') or addrpub.startswith('035cd185') or addrpub.startswith('02e0a8b0'):
print(f"2^{exp} - 2^{exp+1} | PUB : {addrpub} | PVK : {hex(a)}", end = '\n')
If fortune is on your side, a single core of a computer is sufficient for you.. Good...Luck...Luck...And....Only....Luck