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Topic
Board Development & Technical Discussion
Re: Pollard's kangaroo ECDLP solver
by
satashi_nokamato
on 19/04/2024, 14:45:09 UTC
When we restore searching from a saved work file, it only shows the first key in input file after the end range, so what happens to other keys we input for search?

And if we have a speed of 1000MK/s, it would divide by the number of keys right? meaning half the speed is used to search for the second key if we input 2 keys? If that is the case then the expected time should double if there is more than 1 key.
Thus having 4 keys to search for a 130 bit key could take up to 2**68 operations, correct?