Using the function above, and setting the block character values for each position “234134”, we get the first word as follows:
234134
LwE~T1
aseatb
You lost me here. I did figure out that wE~T is seat, but I couldn't figure out what's 'L' and '1'. Why did you turn them into 'a' and 'b'?
- 'a' points to L, top right.
- 'b' points to '1' top left
How did you work out the "top right" and "top left"? We both didn't figure out how the OP decides the silver card placement in the beginning, as far as I can tell.
Let me clarify this, it's really difficult to look at it manually and solve it, but it's possible. Basically we assign one value from 1234, each meaning top left, top right, bottom left, bottom right (I'm not sure what directions these actually are in my code, as the puzzle is a bit different in my mind). Each character in a 6-char cipher block maps to one of these. For C1, this value is 234134.
234134
LwE~T1
aseatb
L corresponds to 2 -> choose 1 of 4 directions, the direction that we assign as 2. Read the connection of the direction, and we get "a".
1 corresponds to 4 -> we choose 4th direction. Read the connection, and we get "b".
If you're asking how I managed to find it, I kind of manually tried in my program, which prints the resulting mapping combinations for any given string with 6 numerical characters ranging from 1 to 4. If I input "111111" then I try to read one direction connection for all characters in C1 or C2, like "choose the black card character bottom right of the chosen silver card character, given 1 out of 12 placement.
Basically each character in a 6-character cipher block corresponds to exactly one direction. And this value differs for the cipher block characters in C2. Consequently, "a" and "b" are order markers, taking their value from the word "incomputable", so 9th and 10th letters, which correspond to first two words. Then, each word has one of the letters in their beginning.