Post
Topic
Board Bitcoin Discussion
Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
by
mohammedlaoui
on 24/04/2024, 11:06:59 UTC

In the context of the polynomial generated using the Lagrange interpolation method in Sage, the x value represents the variable of the polynomial. It's not directly related to a public key's x value in cryptography. Here, x is the independent variable in the polynomial.

In Sage, when you construct a polynomial, x represents the variable in that polynomial. In the given code:


Code:
R = PolynomialRing(QQ,'x')                                 
f = R.lagrange_polynomial([(0,1),(1,3),(2,7),(3,8),(4,21),(5,49),(6,76),(7,224),(8,467),(9,514),(10,1155),(11,2683),(12,5216),(13,10544),(14,26867),(15,51510)])
for i in range(16):
    print(f(i))
Here, x is the variable in the polynomial f. So, x in the polynomial formula is just a placeholder for the variable in the polynomial equation, and it doesn't have any direct relationship to a public key's x value in cryptography.