What has house edge to do with expected losses in a win/lose ratio??
The house edge determines the percentage of bets you will lose long-term.
For example, if the advertised house edge is 0,5%, then long-term you should lose 0,5% of your bets placed
House edge will be accounted for wins and losses profit wise, not for the game outcome :: .
The chance for a win is only over 42% while the rest is accounted for losses or pushes. In other words, your calculation makes 0 sense.
In Black Jack, the house edge
will not be accounted for wins and losses profit wise, because when you win a Black Jack you win 1,5 bets and you can split cards and double bets when you have an additional expected value towards the dealer.
So even though the chance to win a hand is only 42%, with the additional Black Jack payment or 1,5 bets and the additional expected value when splitting cards and doubling bets, the house edge will add up to only 0,5% instead of 8%.
If you are in the possession of a basic logic, you should be able to immediately conclude that winning only 42% of the hands (= 8% house edge), can not be the house edge when the advertised house edge is only 0,5%.
People not in the possession of a basic logic should not post in this thread, because they are not qualified to do so!
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Another case where you didn’t get your facts straight, very sad to see. You should use your time for something useful and not for this nonsense.
You are obviously the one who didn’t get your facts straight!