Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
But why don't those who understand software use their codes in non-standard mathematical operations?
Why do they always think of formulas like A = B - C (x.y) with ready-made logic?
Even the A - B - C - x - y that is currently being written is mathematics.
Why do they always think of formulas like A = B - C (x.y) with ready-made logic?
Even the A - B - C - x - y that is currently being written is mathematics.
Because illogical thinking cannot manifest itself as working software? At some point a logical contradiction occurs (unless you like software that includes intentional bugs), and it may be spotted even before attempting to touch a keyboard. Otherwise, the lesson is learned the hard way, but with no doubt that moment occurs sooner or later. But what stops you from giving it a shot, if you believe it's not a waste of time (or life); what are your results, besides spreading around your own beliefs, backed by nothing and impossible to prove or test?
Can you be patient a little longer? Because when the time comes to prove it, I will just say that I did it.
My hardware is not very high, so it may take a few weeks.
After that, I will publish the HEX code SHA256 here before transferring it. After that, I will just sit and watch.
I am not telling you to write illogical software, if you know MATHEMATICS. This includes basic statistics, PROBABILITY PERCENTAGE... I can list many reasons.
I can show many examples and proofs for this. Actually, I don't have to, you will understand this when I am done.
You want maths? here's a bit of maths for you. You have N=3(mod 4), tell me what N is. It's math, it's reversible right? I recommend at least reading how hashing functions, Ripemd and sha work before spewing nonsense. Same goes for the brainless guy.
Did you really write with such intelligence?
Even in the question you wrote, there are PROBABILITY values that I wrote in capital letters.
Really?Let me give you the answer, don't force it.
N = 4k + 3
That is;
If
k=0 then N=3
k=1 then N=7
k=2 then N=11
k=3 then N=15 ....
That is, there is no exact result for the N value. But there are PROBABILITY results. LOL
