Re: how will the Bitcoin security hold up as miners' rewards decrease

I also wonder when the final halving technically occurs. How is it programmed? Is there a hard stop, or does it stop when the reward is less than two satoshi and no more halving is possible?

yep each halving is just 1 bit less of the reward which the translates binary to decimal to a number you can recognise
the very last halving is where the final 1bit becomes 0

.. i understand your a newbie so i wont rip apart your other errors i found in your article, but enjoy learning about bitcoin. there is much to learn

And after 1 bit becomes 0 is the network programmed to stop 'dividing/cutting' it or will it forever divide 0 by 2 (only to get 0 again) every 210 000 blocks?

divide binary 0 by 2?? you have no clue .. there is nothing to divide.. you cant divide a single binary bit.. learn math and computer science and physics
if a binary bit is 1 it "switches" to 0.. and so (in integer/human form..) zero block reward from the native supply. so that its just tx fee total that becomes the payment to miners

I do understand the binary math; probably, I haven't correctly expressed myself. The question was whether (1) the networks eternally continue trying to remove another bit and distribute zero reward or (2) it has some condition like "if after halving procedure block reward=0 then stop sending block reward and stop halving procedure"?