you could convert binary keys to hex easily and then run keyhunt
Hmmm, I am not sure if Keyhunt can do that. Just to be clear. I want to check .txt file of eg. 1 000 000 hypothetic 256bit private keys (not consecutive, more like random) against list of addreses. Keyhunt can't do that I think.
Best
Regards
Damian
if the list is that small then
import secp256k1 as ice
keys = []
addresses = []
with open("keys.txt", 'r') as vf:
for line in vf:
for word in line.split():
keys.append(word)
with open("addresses.txt", 'r') as vf:
for line in vf:
for word in line.split():
addresses.append(word)
for i in range(len(addresses)):
for k in range(len(keys)):
if ice.privatekey_to_address(0, True, keys[k]) == addresses[i]:
with open("Found.txt", "w") as file:
file.write(f"Found: {keys[k]} Address: {addresses[i]}")
file.close()
print("FOUND")
exit()