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Scraped on 15/04/2025, 10:56:20 UTC
Let's guess puzzle 69, how long will it take to solve this problem?Six months, one year, three years or even longer.
Regarding prefixes:Is it faster to use the birthday argument to find hash160?Has anyone paid attention to this?

I can do it in 29671 days, I only need around 10 $ every day, to keep a steady rate. I'm already at 0.003276% of the scan. Are you in?

Yes, you can definitely force the H160 values/prefixes to repeat to your liking so that birthday argument applies. It's totally wrong to think that the birthday paradox simply applies for two people sharing the same birthday, whichever birthday it may be. It of course applies to two people that share the exact birthday you want them to have. Your mentor / ocult clan leader that obliges you people to pollute this thread every time the air starts to clean itself up,  is spot on!
i dont understand how we imply the birthday paradox in kangaroo method how is a random jumps will yield the same point at some timeSTEP
Original archived Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
Scraped on 15/04/2025, 10:50:53 UTC
Let's guess puzzle 69, how long will it take to solve this problem?Six months, one year, three years or even longer.
Regarding prefixes:Is it faster to use the birthday argument to find hash160?Has anyone paid attention to this?

I can do it in 29671 days, I only need around 10 $ every day, to keep a steady rate. I'm already at 0.003276% of the scan. Are you in?

Yes, you can definitely force the H160 values/prefixes to repeat to your liking so that birthday argument applies. It's totally wrong to think that the birthday paradox simply applies for two people sharing the same birthday, whichever birthday it may be. It of course applies to two people that share the exact birthday you want them to have. Your mentor / ocult clan leader that obliges you people to pollute this thread every time the air starts to clean itself up,  is spot on!
i dont understand how we imply the birthday paradox in kangaroo method how is a random jumps will yield the same point at some time