Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
🔮 Curvature in Bitcoin's key space?
In physics, the curvature of space-time allows a ship (hypothetically) to take a shortcut, like in a warp drive. In Bitcoin's key space (a space of 2²⁵⁶ possible private keys), finding a specific key is like searching for a grain of sand in an entire universe. But... what if we could "curve" that space somehow? A lot of Netflix, right?
In physics, the curvature of space-time allows a ship (hypothetically) to take a shortcut, like in a warp drive. In Bitcoin's key space (a space of 2²⁵⁶ possible private keys), finding a specific key is like searching for a grain of sand in an entire universe. But... what if we could "curve" that space somehow? A lot of Netflix, right?
You aren’t fighting the entire 2²⁵⁶ universe—just a 2⁶⁹ keyspace.
My approach:
Instead of using secp256k1 for key derivation, I propose:
Generating all possible uncompressed Wallet Import Formats (WIFs) within the 69-bit keyspace (specifically, from 0x10000000000000000 to 0x1FFFFFFFFFFFFFFFF).
Optimizing the process using warpseeding—a custom acceleration method combining SHA-256 hashing and Base58 encoding for faster WIF generation.
Checking each WIF against the Puzzle #69 address to identify the correct private key.
Bypassing curve operations entirely
P.S. Converting each WIF to a Bitcoin address (which does require secp256k1, but only after filtering).
How do you filter characters after "5HpHagT65TZzG1PH3CSu63k8DbpvD8s5i" ?
You just have to know everything, don’t you?
Well, I’m just asking because it’s impossible to break through the 51 – 33 = 18 missing Base58 characters—unless there’s some trick. If the missing characters follow a predictable structure (e.g., repeated segments, checksums, or known prefixes/suffixes), then maybe. But there is no pattern here—only the first 33 characters. Checksum + segments = lol?
