Post
Topic
Board Development & Technical Discussion
Re: P = A[X1, Y] - B[X2,Y]
by
PROFIGROK
on 27/08/2025, 17:43:19 UTC
Yes. But just when the only information you have is that the private key is anywhere between 1 and n - 1.

In other words: good luck finding the specific pair of points that add up to P (or one of its equivalent endos).
How to calculate the private key for my example?