So what you're saying is 25/173366316979 *(round time in weighted shares + shelved shares from previous round)= payout for that block. As long as those shares in the entire pool don't out weigh the total amount of shares for the current round.
No, the payout for the block is always 25 BTC. They are paid out to the topmost 173366316979 shares in the stack ("shelf"). If this is an unlucky round (greater than 17.3 Billion shares accepted) then these will all be from the current round, and some shares from the current round will be shelved to hopefully be paid out later. If it is a lucky round, all shares from that round will be paid, and whatever shares are on the top of the stack will be paid out until a total of 17.3 Billions shares are paid out. These shares may be from the last unlucky round, or if there has been a run of good luck, you may have to go back several unlucky blocks.
I guess I should have been more specific to what I was asking here. I'm trying to figure out what a payout would be for an individual miner, not the whole pool. There's no way for the user to see what his shares on the shelf are from unlucky round, but going by what their weighted averages are, you can guess as a payout.
So is that formula how it's figured out correct? What I'm asking is, are the payouts calculated 25/173366316979(100000+50000)=0.0000216305 , where 100,000 is the current round shares and the 50,000 is from a previous unlucky round that made it? So 150,000 is just something for an example.