Anybody have an idea? I think the number on the coin is 5784623964023x2 or 5784623864023x2 or 5784623064023x2. These numbers are on each first coin of all 6 sets. I tried to multiply etc... but couldn't decipher it. If anybody could, send me a portion(No amount is too small!). 
.S. Here is the link : http://i.imgur.com/CeBoEa8.png . Download the image and just zoom it.
~~MZ~~
57846239640235784623964023 Can be factorised as primes which is what is done with the sepc256k1 curve where F = 2^256-2^32 etc (can't remember exactly).S. Here is the link : http://i.imgur.com/CeBoEa8.png . Download the image and just zoom it.
~~MZ~~
http://www.wolframalpha.com/input/?i=57846239640235784623964023
Because there is a reverse R I thought these coin numbers were used to find a point on the curve since doubling a point (ie x2) requires a reflection of R ie 2P = Я because it's the only time R is used in math and its reversed.
Basically I think this is how you find the private key for the ฿1
Other things to think about:
Famous Russian princess? Anastasia
"I like da Bitcoin" I like yes Bitcoin?
A lot of this video is similar to the original Bitcoin video from weusecoins.com (the OLD and new video)
I've kinda given up, because why run a contest if you don't keep up with it.
I don't follow what you say about reversal.
You gave idea to try playing with the numbers again. Repeat the number 6 times to get a big number:
578462396402357846239640235784623964023578462396402357846239640235784623964023
But it does not work since it is too big
>>> 2**256
115792089237316195423570985008687907853269984665640564039457584007913129639936
Without repeating the numbers 6 times, all the numbers come out very small, and I don't think the private key will be a small number.
But above is too simple. It does not use enough of the other clues, like the whitepaper and the long code that started with 9...
Which long code starting with 9?
I think its this one:
Code:
9e]IW8lnJN;J[88U316;JA!c:,>1Q9LViK;Jnrr;e+2A5m&]:24`D9/(-@=>3p(9km[F9m UnV9JCQC<,?Js;gE:=:fTe8A6)E>:2*.=<^g.K>"2XO;,pL`6r@lA:If2E;gE::<-i2'@73C q9PS3!=$q%F9iP:_=_]fJ:2+B]9NXo"9mL5':fLt=>'a=1=Apqd9h0/4@mj1<<(9b=[P&e@ r+Iu;-.OY:O+oW9e^*&?Q#6Ypsm=D^r7