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Development & Technical Discussion
Re: AttackerSuccessProbability(0.3,1)=0.627749
by
amaclin
on
30/10/2014, 13:08:11 UTC
Quote from: Sergio_Demian_Lerner on October 30, 2014, 01:05:17 PM
So the problem with my interpretation is that I was not considering that the attacker could catchup after an infinite number of steps/time...
Yes. Thank you. You said all my words in one sentence.
Upd: I am not sure that my calculations are correct