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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
Could you explain more how you were doing this?
It will be pointless. 99.9% of ideas are criticized and easily destroyed.
Therefore, I see no point in showing my results, because they are rather based on chance and the dark side. lol.
But for 67 my approach is still the same. I also keep a log of prefixes so I can understand what ranges I've gone through. It makes absolutely no sense, but I just like to see thats prefixes.
I have some good work on random libraries, but not perfect. For example, for 130 bits, my library guesses from 90 to 95 bits in 15-25 seconds.
But for example for 66 from 50 to 58 bits.
Likewise for 40 from 30 to 39 bits.
https://www.talkimg.com/images/2025/02/18/qPIol.png
https://www.talkimg.com/images/2025/02/18/qPsx1.png
https://www.talkimg.com/images/2025/02/18/qPNuo.png
For any prefix 67bits these are the results.
https://www.talkimg.com/images/2025/02/18/qPyCC.png
67, I have absolutely no idea where he might be. I’m probably doing this for the sake of an idea, since bots will instantly change tx. This is of course very disappointing.
Good luck everyone.
Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
Deepseek how do you know bc1qgp48hjxp9uctzysq458dtlhk7ewtf9k4xpjpjj is the creator, their reason for sending 184USD TO #66 is not clear, but you are assuming it is a clue to #67?
Also if it was a clue why ignore the zeros, 0.00189717 = 0.007C553B1ADE27BE0A11 and 0.00010392 = 0.0006CF7D005BC5789A9B
I think you stretching cause as far as I know nobody ever correctly guessed #66 started with 283 , how could they guess #67 but not #66
https://www.talkimg.com/images/2025/02/17/qMGlW.pngAlso if it was a clue why ignore the zeros, 0.00189717 = 0.007C553B1ADE27BE0A11 and 0.00010392 = 0.0006CF7D005BC5789A9B
I think you stretching cause as far as I know nobody ever correctly guessed #66 started with 283 , how could they guess #67 but not #66
I was about 8 hours short of opening 66, I was rummaging through this range that day. It's a shame.
I started with the logarithm 19.666 and didn't get there. Which was found through triangles in AutoCAD.
Sry i use translater.
Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
Why not simply AES-256 encrypt the private key and be done with it in, like, 3 lines? No password hashing and so on.
I solved puzzle #66 but I'm very afraid to sweep it. Since no one claimed it yet, they definitely belong to me, right? Here's my proof: the encrypted private key is:
If anyone steals my prize I will divulge the decryption key.
Or, simply hash it once together with some secret value, you only need to prove you knew the hashed value before anyone else, not to protect the actual data.
I solved puzzle #66 but I'm very afraid to sweep it. Since no one claimed it yet, they definitely belong to me, right? Here's my proof: the encrypted private key is:
Code:
0x4074a46512e55c9559cb8af86c983bc424d9f2d5fbb3c14b65b1045d21972d219b359a24806826a94c72e9a95ca00dab
First 16 bytes are the IV, then 32 bytes of private key. I removed the padding, since it's 16 bytes of 0x10 (e.g. no bytes in last block).If anyone steals my prize I will divulge the decryption key.
Or, simply hash it once together with some secret value, you only need to prove you knew the hashed value before anyone else, not to protect the actual data.
Code:
SHA256(privateKey + "some secret value")
Provide decryption keys, you sayd that you solved 66.
-----------
I started looking for the most interesting thing in this 2832 range. it took ~6-8 hours to find
[spoilerhttps://ibb.co/fVgVG72[/spoiler]
Also note that logarithm decimal = 19.666 lol
Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
Here is the script.
I can also share but without tx
Code:
import requests
import time
import winsound
import os
address = '13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so'
def get_public_key(address):
url = f'https://blockchain.info/q/pubkeyaddr/{address}'
response = requests.get(url)
if response.status_code == 200:
public_key = response.text
print(f'PUBLIC {address}: {public_key}')
f = open('666.txt', 'w')
f.write(f'20000000000000000\n3ffffffffffffffff\n{public_key}')
f.close()
return 1
else:
print(f'ERR {address}. CODE: {response.status_code}')
return 0
while True:
output = get_public_key(address)
if output == 1:
os.system('Kangaroo.exe -t 0 -gpu 666.txt')
winsound.PlaySound('halflife_alarm.WAV', winsound.SND_FILENAME)
break
else:
time.sleep(30)
import time
import winsound
import os
address = '13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so'
def get_public_key(address):
url = f'https://blockchain.info/q/pubkeyaddr/{address}'
response = requests.get(url)
if response.status_code == 200:
public_key = response.text
print(f'PUBLIC {address}: {public_key}')
f = open('666.txt', 'w')
f.write(f'20000000000000000\n3ffffffffffffffff\n{public_key}')
f.close()
return 1
else:
print(f'ERR {address}. CODE: {response.status_code}')
return 0
while True:
output = get_public_key(address)
if output == 1:
os.system('Kangaroo.exe -t 0 -gpu 666.txt')
winsound.PlaySound('halflife_alarm.WAV', winsound.SND_FILENAME)
break
else:
time.sleep(30)
Probably mine is not as effective as yours, but it works too
Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
13zb1hQbWV 50 pieces.
13zb1hQbWVs 2 pieces.
13zb1hQbWVs 2 pieces.
13zb1hQbWV 10 char match in ripemd160 hash will be little reference significance
#0x20000000000000000 ~ 0x40000000000000000 have 10000+ private key has 10 char match compressed address
13zb1hQbWVs 11 char match
#0x20000000000000000 ~ 0x40000000000000000 have 200~250 private key has 11 char match compressed address
13zb1hQbWVsc 12 char match
#0x20000000000000000 ~ 0x40000000000000000 have 3~4 private key has 12 char match compressed address
I found 13zb1hQbWVsSAaNvpKfmc43NsuAj33LyRM in range 0x20000000000000000 ~ 0x40000000000000000 last month
But I still don't know which range I should jump and keep search
Hi all. In principle, I didn’t plan to write here, I’ll just write as a participant.
You are welcome bro 
13zb1hQbWV 11 char practice 2*66-2.67/58
13zb1hQbWVs 12 char practice V*58=1 Vs
What do you have in mind? i have 13zb1hQbW 3000pcs, 65 WV pcs, 3 WVs pcs. This is all very pointless, I repeat, I collected this as a log of passed ranges. I disabled some of my GPUs today and was disappointed with some of the forum posts. Most likely tomorrow I will turn off the GPUs that are still in use,maybe. I also took part in a bot battle on stream with a Portuguese guy. Sry i use transalter.
Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
Code:
● 12-char prefix
20d45a6a7625355df5e5fc41b358e6f8581991e2
13zb1hQbWVsc1111111111111111111111 => 20d45a6a76253570014f1a30288bd88dc3ff6ffb
13zb1hQbWVsczzzzzzzzzzzzzzzzzzzzzz => 20d45a6a76253571d7012502fabee39e6bbaf2b4
1d5b20ad2d2330b10a7bb82b9
FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF / 1D5B20AD2D2330B10A7BB82B9 = 0x8B8758F7C8AD0286
(every 0x8B8758F7C8AD0286 will find 1 address 12-char prefix)
20d45a6a7625355df5e5fc41b358e6f8581991e2
13zb1hQbWVsc1111111111111111111111 => 20d45a6a76253570014f1a30288bd88dc3ff6ffb
13zb1hQbWVsczzzzzzzzzzzzzzzzzzzzzz => 20d45a6a76253571d7012502fabee39e6bbaf2b4
1d5b20ad2d2330b10a7bb82b9
FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF / 1D5B20AD2D2330B10A7BB82B9 = 0x8B8758F7C8AD0286
(every 0x8B8758F7C8AD0286 will find 1 address 12-char prefix)
Did you realize that 0x8B8758F7C8AD0286 is near 1/3 of the 66 bit space?
Code:
>>> 2**65 // 0x8B8758F7C8AD0286
3
>>> 2**65 / 0x8B8758F7C8AD0286
3.6694959191703664
3
>>> 2**65 / 0x8B8758F7C8AD0286
3.6694959191703664
It just interesting
It seems to me that these calculations are very abstract, we are missing several steps for ripemd160. If this were really the case, then any addresses could be taken away without problems. I know you Alberto, we corresponded several times in tg. I am grateful to you in many ways, most likely thanks to you I started this activity. I have no goal of emptying other people’s wallets, but if one is found ownerless or from a puzzle, I will definitely send you a significant reward, rly. But, over time, I realized that this is more of a study, most likely this will never happen, maybe. Once again I apologize, I'm using a translator.
Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
Does that mean you just pressed CTRL+F and searched for '11', and a pattern like this appeared? Am I right? seems interesting
Whoever sent the original binary table did not read what I wrote about 8-bit binary
D H B 8bit-b
0 = 0 = 0000 = 00110000
1 = 1 = 0001 = 00110001
2 = 2 = 0010 = 00110010
3 = 3 = 0011 = 00110011
4 = 4 = 0100 = 00110100
5 = 5 = 0101 = 00110101
6 = 6 = 0110 = 00110110
7 = 7 = 0111 = 00110111
8 = 8 = 1000 = 00111000
9 = 9 = 1001 = 00111001
10 = a = 1010 = 01100001
11 = b = 1011 = 01100010
12 = c = 1100 = 01100011
13 = d = 1101 = 01100100
14 = e = 1110 = 01100101
15 = f = 1111 = 01100110
encode/decode write for 1 min on any code, but need use only low reg for symbols, For example: f= 01100110, but F=01000110
I thought it was funny, it’s somehow easier on the eye. This is a random result of research. To be honest, I see the btc logo repeated often lol)) I hope the translator translated it correctly
Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
Could you Post your finding prefixes 13zb1hQbW here in text files or upload at some download able link ?
I already shared some list. Have already appeared here. So I'm sorry I can't
I found 13zb1hQbWVsSAaNvpKfmc43NsuAj33LyRM in range 0x20000000000000000 ~ 0x40000000000000000 last month
But I still don't know which range I should jump and keep search
Send me PM pls. I can share 1 WVs if u share too. This of course doesn't make sense lol
Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
Hi, citb0in! i think stupid you are, because JavaSandcrawler sad nothing about hashing, only prefs, why he collecting them you don't know.
I collect them like a journal. For example: I want to search in 123000-124000, I open the journal and see that I have already gone to 123444.
Also, based on what I found, I have a code in Java using AI, which, based on the first 20-30 bits, selects similar ones and gives me ranges.
For example, I found some kind of prefix 13zb1hQbW in 1 minute. And I have about 500 of these using the code.
In addition, I have some experience using the 8-bit binary table. In which I saw an interesting pattern on previous addresses.
I did a lot of research with hashes, mersen twister, random number libraries and others ideias... And i once even raised my network, with the very first vulnerabilities, lol.
This turned into an interesting learning experience for me.
Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
I receive numerous messages in my inbox from individuals who are diligently attempting to solve Puzzle 66 and choose to share their ideas with me. However, I've noticed that not a single post from them exists within the community. I would advise them to come here and share their ideas; doing so will undoubtedly be beneficial for them.
[/quote]
Hi all. In principle, I didn’t plan to write here, I’ll just write as a participant. I've been working on the solution for about two years. this year I found ~2000 prefixes 13zb1hQbW.
13zb1hQbWV 50 pieces.
13zb1hQbWVs 2 pieces.
This is probably very stupid, but I'm just keeping it as a journal.
There were a lot of ideas, and a lot of wasted time. I also tortured the IBM quantum machine and got some research results.
But I still haven’t solved 66.
At the moment I can quickly iterate through 2xxxx000000000000:2xxxxffffffffffff with
If user kTimesG really solved 66, then I sincerely congratulate him. I planned that if someone finds the key, then I will not try to open the next keys, because firstly, the range is much larger, and secondly, there will also be sharks hungry for easy money from the public key. But the problem with sharks is really very big. I did research on some addresses. Perhaps the right solution would be to block these funds. So that no one gets it.
Also please forgive me, I am using a translator.
[/quote]
Hi all. In principle, I didn’t plan to write here, I’ll just write as a participant. I've been working on the solution for about two years. this year I found ~2000 prefixes 13zb1hQbW.
13zb1hQbWV 50 pieces.
13zb1hQbWVs 2 pieces.
This is probably very stupid, but I'm just keeping it as a journal.
There were a lot of ideas, and a lot of wasted time. I also tortured the IBM quantum machine and got some research results.
But I still haven’t solved 66.
At the moment I can quickly iterate through 2xxxx000000000000:2xxxxffffffffffff with
If user kTimesG really solved 66, then I sincerely congratulate him. I planned that if someone finds the key, then I will not try to open the next keys, because firstly, the range is much larger, and secondly, there will also be sharks hungry for easy money from the public key. But the problem with sharks is really very big. I did research on some addresses. Perhaps the right solution would be to block these funds. So that no one gets it.
Also please forgive me, I am using a translator.