OK, so basically the same old shit: "I don't have anything palpable, just some idea that everyone says it doesn't apply, but what do they know? I'll just throw some lateral blah blah instead of some actual statements with proofs, because hyped up emotions are better than logical thinking". Too tired of that non-sense.

Does math cost money? Does logic, theorems, proofs, cost money? All of those were always made free to everyone, for nothing in exchange except dying poor and oh, remaining in history books for all eternity. just look at the last 5000 years of human progress.

You know what costs money? Absolutely everything that you can't do by your own hands. That's almost literally why money exists in this world. Also, I changed my mind. Since you can't code, but I can, I would charge you around 500 million $ if you want your idea put in practice. Also, I can not guarantee your idea would actually work, since it's your idea, not mine. I am just charging for the wasted time on my side, you will also pay for all the equipment and resources and electricity needed to implement whatever you have in mind.

Not the other way around, because I don't care about your idea, but you seem to care about your idea being coded and "automated", if I am not mistaken.

We are all very excited that you finally decided to be ready to share with us these exciting breakthroughs.

It was already more than 24 hours since the last range splitter / range reducer / point divider post was brought upon our limited attention. We need to never let those ideas die off! No matter how often it is explained why it does not work and why it can not work, and why it will never work, and how it actually makes things much slower, instead of much faster, it is a true inspiration to see the same question and the same idiotic idea repeated over and over and over again by new and old users.

Let's not break the cycle! Who cares that solving any problem is more or less just a matter of having enough money to spend, to actually be able to afford computing the solution? Give me a few million $ and I can solve all of those puzzles for you in less than a few months, if not faster - how about that as an actual end to all of this?

Yeah, there are some geniuses here that can crack EC and even 135-160bit is not a problem for them!

There are several methods were proposed already:
1. Magic patterns.
2. Magic divisions.
3. Magic circles (my favourite!)
4. Magic range reducing.
5. Magic BSGS variants.
...and some even more interesting and promising methods!

The only issues usually are:
1. They don't have coding skills.
2. They don't have a good computer (quantum?)
3. They don't have any friends with coding skills or a good computer.
4. They don't have proper settings for JLP app.
But they know 100% working methods how to break EC and always ready to help.
I hope one day someone will help them to take all the money and finally close these puzzles!
But please don't ask me about it, I'm too old for this sh*t magic.

I'm working on 135, but it will take a lot of time, I'm not in a hurry. If you think that you compete - welcome But 99% of people even cannot correctly calculate chances and cost of this game.

I don't have your email or telegram, I will do the transfer Tomorrow at 15:30 (Brasilia), Live on youtube: https://www.youtube.com/live/CjxjkDEE43s
The Address: 197kFKvMHoRJPXktc8xJwMjeTuE9xijBQ

Division by 2 just means to multiply by 1/2 mod N.
1/2 just means 2's inverse so that 2*x = 1 mod N.
Inverse of x mod N just means x^N-2 mod N (Fermat Little Theorem).

Let's take F = { y(x) = 2^x mod 11, 0 < x < 11 }

and some known y = 5: 2^x = 5 mod 11

"Divide" public key by 2: 2^x/2 = 5/2 mod 11

2^x-1 = 2^-1 * 5 mod 11
2^-1 = 2^11-2 mod 11 = 6

So: 2^x-1 = 5*6 mod 11 = 8

Great, now you have to find x - 1. Repeat? Sounds like nothing really changed.

Let's take F = { (x, y) = [k]G, 0 < k < N }

and some known (x, y) = Q: [k]G = Q

"Divide" public key by 2: [k/2]G = [1/2]Q

[k/2]G = [2^-1]Q
2^-1 = 2^N-2 mod N

So: [k/2 mod N]G = [2^N-2 mod N]Q

Great, now you have to find k / 2. Repeat? Sounds like nothing really changed.

If you fall into the trap that k is somehow half the size now, remember this:
1. Division of a field element means multiplying the element with the divisor's field inverse.
    k is not an integer in an infinite field, but a finite field. You can't just half it's value, that only makes sense in an
    infinite field, and only if such an inverse really exists.
2. Groups do not have multiplication operation, only addition. There's no such thing as multiplying or division of elliptic points, they form a group, not a field. "Point multiplication by k" just means adding the point to itself k times. "Division by k" means adding the same point to itself k^N-2 mod N times. You need to respect the definitions of what something can be called a "group" or "field", "finite" vs "infinite", not invent or borrow properties from different structures. It can't work.

Hi albert0bsd, could you leave me your email in a private message, I have an idea for your keyhunt program, business suggestions!.
Your problem is the .exe and windows stuff

Don use it on windows, compile it your self in a WSL environment or native linux

The lastest version is Version 0.2.230519 Satoshi Quest it provide an increment of speed X2 compared with previous version