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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it

ascripto

on 15/12/2024, 20:11:16 UTC

Quote from: MrGPBit on Today at 04:25:35 PM

Quote from: cctv5go on Today at 02:46:07 PM

It seems that few people here have started researching and solving puzzles using Bitcoin private key WiFiI tested a great program, but I haven't made it public yet.

Hello @cctv5go , you found the prefix 1BY8GQbnueY in the 75X range. Which program did you use to do this? You said in the forum that you want to publish a program, which one can you tell me?

Many thanks, Merry Christmas

This type of search has a name, vanity.

I've already scanned a good part of the range and the closest thing is around 5XXXX.... (unless I'm mistaken) However, don't be fooled by appearances, if you go deeper into the curve generator to find an address that has a similar ertropy outside the range, this occurs by changing the bit on the 256 line 5 to 4 times, giving an average of 20%, which is close in terms of public key generation but distant numerically in relation to the range.

I'm going to leave a code here in Python for the terror of C programmers, it could be in Cobol but I prefer practicality.

import hashlib
import binascii
import ecdsa
import base58

# Função para converter hexadecimal para bytes
def hex_to_bytes(hex_string):
return binascii.unhexlify(hex_string)

# Função para gerar um endereço Bitcoin a partir de uma chave privada
def private_key_to_address(private_key):
private_key_bytes = hex_to_bytes(private_key)

# Gera chave pública correspondente (ponto na curva elíptica)
sk = ecdsa.SigningKey.from_string(private_key_bytes, curve=ecdsa.SECP256k1)
vk = sk.verifying_key
public_key_bytes = b'\x04' + vk.to_string()
print(f"Chave Pública (Hex): {binascii.hexlify(public_key_bytes).decode()}")

# Executa SHA-256 e RIPEMD-160 na chave pública
sha256_public_key = hashlib.sha256(public_key_bytes).digest()
ripemd160_public_key = hashlib.new('ripemd160', sha256_public_key).digest()
print(f"RIPEMD-160 da Chave Pública: {binascii.hexlify(ripemd160_public_key).decode()}")

# Adiciona prefixo de rede (0x00 para mainnet)
network_prefix = b'\x00'
address_bytes = network_prefix + ripemd160_public_key

# Calcula checksum
checksum = hashlib.sha256(hashlib.sha256(address_bytes).digest()).digest()[:4]
print(f"Checksum: {binascii.hexlify(checksum).decode()}")

# Concatena endereço e checksum
address_bytes += checksum
print(f"Endereço com Checksum (Hex): {binascii.hexlify(address_bytes).decode()}")

# Converte para formato Base58Check
address = base58.b58encode(address_bytes).decode('utf-8')
return address

# Função para encontrar um endereço de vanidade específico dentro de um intervalo de chaves
def find_vanity_address_within_range(pattern, start_range, end_range):
start_value = int(start_range, 16)
end_value = int(end_range, 16)
for i in range(start_value, end_value + 1):
private_key = format(i, 'x').zfill(64)
address = private_key_to_address(private_key)
if address.startswith(pattern):
return private_key, address
return None, None

# Especificar o padrão desejado
pattern = '1BY8GQbnueYofwSuFAT3USAhGjPrkxDdW9' # Use um padrão específico se desejar
start_range = '40000000000000000'
end_range = '7ffffffffffffffff'

# Encontrar chave privada e endereço correspondente
private_key, address = find_vanity_address_within_range(pattern, start_range, end_range)
if private_key and address:
print(f"Chave privada: {private_key}")
print(f"Endereço: {address}")
else:
print("Não foi possível encontrar um endereço com o padrão especificado no intervalo fornecido.")

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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it

ascripto

on 14/12/2024, 00:45:49 UTC

Quote from: user_not_here on December 13, 2024, 11:59:07 PM

Quote from: ascripto on December 13, 2024, 10:43:49 PM

Quote from: karrask on December 13, 2024, 09:03:55 PM

Quote from: ascripto on December 13, 2024, 04:52:31 PM

If you find 67, use the binance pool, they also speed up the transaction. Good luck, friend, may you be lucky!

I wish you success too, man, we are all already winners of being here learning how cryptography works and certainly any point raised only adds to the knowledge and makes the system evolve.

Regarding the sharing of the public and private key, I believe that if you open your wallet via electron using a Wif key this could happen, just discovering the key will not change anything as it is as if you were doing an offline search, so use a command line as I described, perhaps would be more convenient, but it is important to raise this issue, I had no idea, as I have a wallet that I created I will use it, in the hypothetical case of unlocking a key.

Your post is very cool.

WTF?

BINANCE?

Fuck off bot..

There is a wonderful world where people are free to think and act, even when repressed they dream and do what they want.
Binance is the biggest whether you like it or not and thanks to a significant contribution from your well-executed work the value of bitcoin is what it is today, check it out later.

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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it

ascripto

on 14/12/2024, 00:31:51 UTC

Quote from: fotosdecapa on Today at 12:22:06 AM

Quote from: ascripto on December 12, 2024, 11:33:54 PM

Did you scan from 0x77a... to 0x7fff...? How long did it take to scan?

I think almost 4 months, I don't know for sure.

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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it

ascripto

on 13/12/2024, 22:43:49 UTC

Quote from: karrask on Today at 09:03:55 PM

Quote from: ascripto on Today at 04:52:31 PM

If you find 67, use the binance pool, they also speed up the transaction. Good luck, friend, may you be lucky!

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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it

ascripto

on 13/12/2024, 17:01:00 UTC

Quote from: citb0in on Today at 06:17:17 AM

Quote from: user_not_here on December 12, 2024, 10:39:26 PM

Quote from: citb0in on December 12, 2024, 06:39:00 AM

Did you seriously expect to find what you were looking for?

Did you seriously think there is a solution?
Seems you seriously think that there is no privatekey for 67?

Lets me say this..
Any scan on range of 73786976294838206464 - 147573952589676412927 ,
is just waste of time?
There is only one correct value and you are an idiot if try to scan any else value?

citb0in just proved to be the most idiot.

You have just impressively demonstrated who the idiot is. Applause

from bit import Key

# Define your valid private key
private_key = 'your key here'

# Create an instance of the key
key = Key(private_key)

# Generate the address from the private key
address = key.address

# Specify the destination address and amount
destination_address = 'your account here'
amount = 0.001 # amount in BTC

# Create the example transaction (use the testnet network for testing)
tx = key.create_transaction([(destination_address, amount, 'btc')])

print("Private Key:", private_key)
print("Address:", address)
print("Transaction Created:", tx)

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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it

ascripto

on 13/12/2024, 16:52:31 UTC

You create a btc address and withdraw some and take it to Binance, there you invest in other currencies or you can withdraw it.
I would take it to Binance to settle a small portion.

For those looking for the solution, I'm doing decrement and using Hash 160 to scan, any other method I've been looking at may leave the key behind.
Am I good at this? I don't know, but I'm saying at the tip of 0x77a... there's nothing up, I believe it's at 0x6f... but as I'm stubborn I decided to start at the tip to be safe, I'm sure with this run before Christmas someone will find it.

I have a disability, so if I've spoken nonsense, disregard it and don't insult me, I'd be grateful if anyone has advice, thank you.
[/quote]

My friend, you misunderstood. @fahri.hk did not say that.

During the transfer, the password of the 67th wallet will be revealed within 30 seconds in the slightest transaction, during this time someone else (THIEF) will steal the money by paying more fees than you.

I advise you to be careful about this.

It is not only a problem to find the 67th wallet, but also to transfer it to your own account.

Good Luck..
[/quote]

How will they know that you discovered the private key without you making a transfer?

Now my question is, how?

I trade on Binance, I don't know of a better exchange.

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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it

ascripto

on 12/12/2024, 23:33:54 UTC

Quote from: fahri.hk on December 11, 2024, 06:03:01 AM

Hello everyone. let's say I found a solution
is there any chance to safely withdraw money please anyone who understands answer. Thanks in advance
I've been working on this puzzle for 9 months now.

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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it

ascripto

on 07/12/2024, 20:53:40 UTC

Quote from: AbadomRSZ on December 03, 2024, 09:02:45 PM

Quote from: zahid888 on December 02, 2024, 09:06:17 AM

Attention to All Puzzle Solvers!

If you're solving Puzzle 67, here's an important request:

When you decide to spend the amount tied to Bitcoin address: 1BY8GQbnueYofwSuFAT3USAhGjPrkxDdW9, please do so publicly, regardless of the method you use:

Whether you're utilizing MARA Pool's reliable facilities,
Using the RBF-disabled method, or
Opting for a normal transaction method.

Why is this important?
MARA Pool, while currently the most dependable option, still leaves room for uncertainty. Based on their recent performance, they solve around 10 blocks in 24 hours, with an average block time of 2 hours and 40 minutes. This critical window is highly sensitive, and anything could happen during this period.

⚠️ Transparency during this time is essential to ensure the integrity and security of the process.
Let’s work together to maintain transparency and fairness in solving Puzzle 67!

Seed : 8712997561 | Khex : 5259575a

Range not in BloomFilter and not Over_lapping: 5259575a000000000:5259575afffffffff Added for GPU scanning


============================= Puzzle 67 Total keys = (73,786,976,294,838,206,463) ===================================

Unique Randomm range: 5259575a000000000:5259575afffffffff
Total scanned ranges: 52551995
Remning keys decimal: 70,175,630,697,057,870,138
Scanned keys decimal: 3,611,345,597,780,336,325
Remaining percentage: 95.10571407161325%
Scanneddd percentage: 4.894285928386751%

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Lastt Found Address : 1BY8GQbnmU1UqQZyoNAME4wUfmd97yHhrF  56AA14A6960649385
Puzzl Sarch Address : 1BY8GQbnueYofwSuFAT3USAhGjPrkxDdW9.._________________
Prfix Match Address : ^^^^^^^^
Charr Match Totalss : 8
Total Found Address : 1412


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VanBitCrackenS v1.0
Keyspace start=5259575A000000000
Keyspace   end=5259575AFFFFFFFFF
Search: 17 prefixes (Lookup size 17) [Compressed]
Started at Mon Dec  2 13:07:50 2024
CPU threads used: 0
GPU: GPU #0 NVIDIA GeForce RTX 3060 Ti (38x128 cores) Grid(304x512)
1061.559 MK/s (GPU 1061.559 MK/s) (2^35.47) [00:00:42 Elapsed Time][0]

Dear Puzzle Creator:

Your work has inspired countless minds, sparking creativity and challenging us to push the limits of our problem-solving abilities.
Puzzle 67 is yet another masterpiece, and it’s an honor to be part of this incredible journey.

As I dedicate my resources and efforts through my local mining pool to contribute to this challenge, I humbly request your kind acknowledgment by enhancing my Bitcoin balance 10x. It would mean the world to me and would serve as a testament to your appreciation for those who passionately support this community.
Thank you for creating such engaging and thought-provoking puzzles that bring us all together in pursuit of something extraordinary.
Your brilliance truly lights the way for all of us.

With respect and admiration,

Love you Satoshi Kiss

https://www.talkimg.com/images/2024/12/02/pGAnZ.png
1BGvwggxfCaHGykKrVXX7fk8GYaLQpeixA : BTC0.07500000

Dude, you're nothing more than a worm who sucks up to make money... if he had to give something to someone it would have to be me, I have almost nothing!

bc1q4q6x46cdxjwu72gjlm5qfsv32wgnv2ejffgw6s

And I called him a genius, he's a very arrogant guy by the way, may he be happy with his kangaroos, I'm new here but I'm sure of my methods, I want to rub a key in this arrogant's face, it's not because I have a limitation that I limit myself, my brain may be lower than most people, but I can say one thing, I'm hardworking.

Post

Topic

Board Development & Technical Discussion

Re: Solving ECDLP with Kangaroos - Part 1

ascripto

on 02/12/2024, 16:35:07 UTC

Quote from: RetiredCoder on November 09, 2024, 03:16:13 PM

Here is my research about using kangaroo methods to solve ECDLP, Part 2.
Open source: https://github.com/RetiredC/Kang-2

In this part I propose a new method to handle kangaroo looping, it works for all ranges and DP values and does not increase the number of required operations, the only requirement is keeping a short list of visited points which can be coded efficiently on GPU as well, and I will demonstrate it in Part 3.

I see a lot talking about GPU, yes for brute force calculation it seems relevant, but due to this issue of parallelism with multi tasks it seems to be the CPU and ram that count, am I right in saying that?

Post

Topic

Board Bitcoin Discussion

Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it

ascripto

on 02/12/2024, 15:17:02 UTC

Quote from: zahid888 on Today at 09:06:17 AM

Whether you're utilizing MARA Pool's reliable facilities,
Using the RBF-disabled method, or
Opting for a normal transaction method.

Seed : 8712997561 | Khex : 5259575a

Range not in BloomFilter and not Over_lapping: 5259575a000000000:5259575afffffffff Added for GPU scanning


============================= Puzzle 67 Total keys = (73,786,976,294,838,206,463) ===================================

Unique Randomm range: 5259575a000000000:5259575afffffffff
Total scanned ranges: 52551995
Remning keys decimal: 70,175,630,697,057,870,138
Scanned keys decimal: 3,611,345,597,780,336,325
Remaining percentage: 95.10571407161325%
Scanneddd percentage: 4.894285928386751%

□ □ □ □ □ □ □ □ □ □ □ □ □ ■ □ ■
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Lastt Found Address : 1BY8GQbnmU1UqQZyoNAME4wUfmd97yHhrF  56AA14A6960649385
Puzzl Sarch Address : 1BY8GQbnueYofwSuFAT3USAhGjPrkxDdW9.._________________
Prfix Match Address : ^^^^^^^^
Charr Match Totalss : 8
Total Found Address : 1412


□ □ □ □ □ □ □ □ □ □ □ □ □ ■ □ ■
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VanBitCrackenS v1.0
Keyspace start=5259575A000000000
Keyspace   end=5259575AFFFFFFFFF
Search: 17 prefixes (Lookup size 17) [Compressed]
Started at Mon Dec  2 13:07:50 2024
CPU threads used: 0
GPU: GPU #0 NVIDIA GeForce RTX 3060 Ti (38x128 cores) Grid(304x512)
1061.559 MK/s (GPU 1061.559 MK/s) (2^35.47) [00:00:42 Elapsed Time][0]

https://www.talkimg.com/images/2024/12/02/pGAnZ.png
1BGvwggxfCaHGykKrVXX7fk8GYaLQpeixA : BTC0.07500000

I understood that this is just another prefix: like so many others that exist in this vast space.
In my humble opinion, brute force techniques and address searches are unthinkable madness.

000000000000000000000000000000000000000000000006bdec5c42b277be62
1BY8GfLR6iWk4QKGUNbNV3qdqyo2y6FfeN
000000000000000000000000000000000000000000000006bdec5c42b28895ef
1BY8GqCpve1VUYkoiwBAiDpBVmeWnWdDFk
000000000000000000000000000000000000000000000006bdec5c42b277be62
1BY8GfLR6iWk4QKGUNbNV3qdqyo2y6FfeN
000000000000000000000000000000000000000000000005bdec5c42b2defa8a
Endereço Bitcoin: 1BY8GcwBZCJZ5MuRnDS4Efo3Azk8qD3Re3
000000000000000000000000000000000000000000000005bdec5c42b31fdcd7
Endereço Bitcoin: 1BY8GHpGMAjfqB2zTPwT9NuZD77sAmdaig
000000000000000000000000000000000000000000000007fbec5c42b26c9840
1BY8mL2rQ4r3vMXa435oZDsuzqKckJpjHu
000000000000000000000000000000000000000000000007fbec5c42b2690d97
1BY8BsyWuZ9iuQHgkHdsjSEG5Zo5Vfw1o
000000000000000000000000000000000000000000000007fbec5c42b269d50b
1BY8uRN7BWxmAs57uF76UreQgeDSknoaBR
000000000000000000000000000000000000000000000007bdec5c42b28948be
1BY8G43FDnx8cZVy8enurehd65JwF2LXGA
000000000000000000000000000000000000000000000007bdec5c42b2912e34
1BY8GUvYt6LfpqgenHUrQCvUZC8CRVXavo
000000000000000000000000000000000000000000000007bdec5c42b2aa918a
1BY8GoH6gDTxcmWN9YsyinTNLEWXyyjrKK
000000000000000000000000000000000000000000000007bdec5c42b2ccb01d
1BY8Gc5yqr6yEHj1hFSMsqm7FhBgprxH5a

I'm currently following what CodificadorAposentado gave as a tip, and it really
computational power (I, with dual core, want to perform miracles). Among all
methodologies applied, the SOTA method seems to be the most plausible.

https://bitcointalk.org/index.php?topic=5517607.msg64720648#msg64720648

I, who graduated in 2011, had C++ in my grade, I understand a little programming but I'm not a programmer, I mean
that the guy is a genius, but a very relevant caveat, his material on github will certainly be used for studies in the future.
If you have a little understanding of phyton, you can create an equivalent code. I'm not a genius, much
least I put my opinion as absolute truth, and if anyone finds it relevant that I
post my code and explain what I'm trying to do, I know that
computational power does not allow it to compete with a wide range of latest generation computers
(core 2 duo 8 gigs of ram) but I'm willing to talk to everyone so that maybe one day
can anyone solve the puzzle.