I will break my word and answer once and only to you because you resorted to insults that are not justified.
In order .
1. I told you that it is impossible to assign a range to the 66th key with hash160 (I do not know such a technique). And there is no open key to number 66.
2. You want to get an algorithm, because you think that there is a grail behind it. There is no grail behind him either.
3. You resorted to searching for my messages for the entire period in order to slander me and justify your supremacy, that you are right and I am still a fraud, which will very much calm your dryness.
It is your right to do so.
But if you read my messages, you noticed that I asked there if I know two different private keys that form the same public key and everything is the same up to the address, whether it is possible to damage the integrity of the curve. I received the answer that no. But everyone immediately, as now, was bombarded with questions, how did you find it, tell us and things like that, when I refused, everyone started calling me a fraud, just like now. Surely the human essence, if it does not get what it wants, then it resorts to insults.
Then I had to ask the moderator to delete the message because there was a very large amount of slander and insults. Now it turns out that this is exactly what should be done.
4. As for why I didn't write for so long, everything is simple.
After the images, I took a break and had lunch on my mind.
and if you notice again, my last message was January 19, 2022, a month later, the war began.
So I live in a country where war has been going on for more than 500 days.
Somehow it was not as written between shelling and bombs.
Now I have calmed down a bit, so I decided to look at the forum and write, and everyone has already seen what happened.
On the one hand, you are being bombarded, on the other hand, they are insulting you. An ideal picture of the universe.

PS
There will be no further answers. Anyone who wants can write anything, even insults in my direction, if it will make him feel better and he will please his pride, please.
If the moderator deems it necessary, he can delete my posts so that they do not give rise to further insults in my direction and deviation of the forum topic from the main goal.

Thank you to everyone who understood my answer.
All my posts written above in no way intended to offend or humiliate any of the forum members or visitors.
Thanks for the peace everyone.

It is not necessary to reduce by so much pk2= 3305730573
Even one character is enough if you can reduce it clearly by 1 digit.
pk2= 3 this is more than enough.

What strange people.
You don't take my word for it, you always want confirmation.
And then this and this.

I regret that I again fell into the trap I fell into a year ago on the same forum. Everyone laughed at me.
No more comments.
Good luck to everyone.





1000000000000000000000000000000000000000
F000000000000000000000000000000000000000

I am very well aware of what I am saying.
Some time ago, I also spoke on this forum about important things that have already been achieved and that are already there, but 99% of the forum members laughed at me and said that this is impossible and that I am making things up because I did not want to open them to them, but they did not listen to my words. believe Let it be their right. That's why I decided not to raise such topics anymore, because people are not ready to take it seriously, because some mathematician or group of scientists said that such and such things are not possible and everyone firmly believes in it.
Unfortunately, the reality is different. Therefore, the situation is exactly the same now. Therefore, I will repeat once again that the range can be allocated, but this brings the decryption not as close as I would like, for this I need one more thing, which I am working on in my spare time.

PS Until I deal with the second part, I will not publish anything and prove some things to someone. It is your right to believe the word or not. Everything will go to society together when the work is completed.
Best regards.

I apologize for not providing clarification.
Find out the range from the public key.

You can eliminate as many numbers as you like.
for example, you can reduce the key by 4 digits from 32 to 28, but for this there will be 65,000 open keys, which I count is a lot.
5 and 6 digits can also be eliminated.
There is even a way to find out the range in which the key is located, but I still don't see a clearer solution than sorting through large numbers of keys.

Hello, help with the code.
I get an error.
line 3, in <module>
     pub=ice.pub2upub('0433709eb11e0d4439a729f21c2c443dedb727528229713f0065721ba8fa46f00e2a1c304a39a77 775d3579d077b6ee5e4d26fd3ec36f52ad674a9b4 7fdd999c48')
AttributeError: module 'secp256k1' has no attribute 'pub2upub'

or can you specify which libraries you actually used, maybe there is an error in this?
thank you

digaran
If you are surprised by the doubling of the original key, then you are still at the very beginning of this "jungle". numbers
I will share with you a little about what awaits you in the future if you have the strength and inspiration to explore the Bitcoin curve.
There are special numbers on the curve that can be used to get exactly 1 digit less.
A third of the number you are looking for.
A quarter of the sought number.
You can get the mirror part of the number you are looking for, which can also be compared with the original.
And this is not even a 10th part of what is there.
You can get a lot.



But as vjudeu said, you can get into an even more difficult situation and get a .....................labyrinth.

I wish you success.

CrunchyF
A question for you.
If you know how to define the range in which the private key is located.
How can I find out the private key?
What is an algorithm?

P.S. I have previously asked this question on this forum people who also boasted that if you know the range you can find out the private key.
They did not provide answers. (Either they don't know how to brag or they don't want to share.)

Thanks for the explanation.

I realized . Sorry for interfering and not understanding.

o_e_l_e_o
I understood you correctly.
Which, according to you, is 2-96, closed inclusions.
Which differ from each other.
But form completely the same

Public key
HASH160
.
.
.
.
The address compressed and uncompressed.

Everything is correct  ?

Gentlemen.
pooya87
HeRetiK
BlackHatCoiner
I appreciate your opinion and your position on the curve.
But, there are at least on the curve, two private keys that are completely different from each other. At the same time they form identical (identical)
Public key
HASH160
.
.
.
.
The address is both compressed and uncompressed.
But, in my opinion, there are 4 such keys. Which can be different, and at the same time form the same source data, up to the address itself. (I can't prove the theory of 4 keys now, I'm working on it.)

P.S.
I can't prove the theory of 4 keys now, I'm working on it. In free time from work.

You are all wrong.
There are at least two different private keys that can be generated, one and the same public key and everything related to it, to the address itself.
But, in my opinion, there are four different such keys. Which can form all the same.

Let's wait, maybe NotATether will answer and dispel the myth.

Alpaste
I also hold this opinion. But I doubted, re-reading the forum posts because NotATether claimed that it is possible to calculate ..
NotATether can dispel the myth?

Hi. I once asked the question of whether it is possible to calculate mathematically in which range the key is.
To which I received a response from NotATether.
If you know the range you can calculate the upper bits of the key.
The question logically asks for answers.
If we know, and we know in what range the key lies (like puzzle 120).
Then why not calculate the upper bits?
What is the calculation algorithm?
Thanks.

I am very grateful to you for your answer.

Hello everybody. The question arose.
How to determine between the two public keys which is bigger? In addition to the subtraction function.
Example.
123456789 private key is not known to us.
His public key.
025004d7d9c2a3b2d675ada618d9ceda55d1f6a9fdf263e24daa8cbea586af2b2b

And accordingly his rival.
12345678a private key is not known to us
His public key.
02fde2347f83e21198fc48b918f5657c188ffcdd8611b39b987230addb91d05d80

Thanks for the answer.

You are right they are and there are many of them.