Renting a docker is taking 2-3 min until is operational.
One docker is containing max 16 cards.
So having something automated for a bigger number of cards, should take 5 min until can start processing.
Renting a quantum is costing minimum 100$/minute

So, let me be clear.

According to this process from here, you say that someone is decoding the public key and extract the private key? So if they do reverse engineering of this process from this script, this means that they can decode almost any public key and get the private key very easy, no?

from ecdsa.ellipticcurve import CurveFp, Point
import time

# --- secp256k1 Parameters ---
p = 0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEFFFFFC2F
a = 0
b = 7

# Generator point G
Gx = int("79BE667EF9DCBBAC55A06295CE870B07029BFCDB2DCE28D959F2815B16F81798", 16)
Gy = int("483ADA7726A3C4655DA4FBFC0E1108A8FD17B448A68554199C47D08FFB10D4B8", 16)

# Create curve and generator point
curve = CurveFp(p, a, b)
G = Point(curve, Gx, Gy)

# --- Compressed Public Key (replace with your own) ---
compressed_pubkey = "02545d2611c823a396ef6712ce0f712f09b9b4f3135e3e0aa3230fb9b6d08d1e16"

# --- Helper: Modular square root (for p % 4 == 3) ---
def modular_sqrt(a, p):
    if pow(a, (p - 1) // 2, p) != 1:
        return None
    return pow(a, (p + 1) // 4, p)

# --- Decompress compressed public key ---
def decompress_pubkey(comp):
    prefix = int(comp[:2], 16)
    x = int(comp[2:], 16)
   
    y_sq = (pow(x, 3, p) + a * x + b) % p
    y = modular_sqrt(y_sq, p)
   
    if y is None:
        raise ValueError("Invalid compressed public key")

    # Adjust sign of y based on prefix
    if (prefix == 0x02 and y % 2 != 0) or (prefix == 0x03 and y % 2 == 0):
        y = (-y) % p

    return Point(curve, x, y)

# --- Brute-force small private key ---
def find_private_key(G, P, max_d=1000000000):
    print(f"🔍 Brute-forcing d such that P = d * G (max {max_d})...")
    start = time.time()

    point = None
    for d in range(1, max_d):
        point = d * G
        if point == P:
            end = time.time()
            print(f"✅ Match found in {end - start:.2f} seconds!")
            return d

        if d % 100000 == 0:
            print(f"Checked {d} keys...")

    print("❌ No match found in given range.")
    return None

# --- Main Execution ---
try:
    P = decompress_pubkey(compressed_pubkey)
    print("🔓 Decompressed Public Key:")
    print("Px =", hex(P.x()))
    print("Py =", hex(P.y()))

    # Try to recover private key
    private_key = find_private_key(G, P, max_d=1000000)

    if private_key:
        print("\n🔐 Private Key Found!")
        print("Private Key (decimal):", private_key)
        print("Private Key (hex):", hex(private_key))
    else:
        print("\n❌ Private key not found in the given range.")

except Exception as e:
    print("Error:", e)

Go to Binance terms and conditions on the Wallet when you want to import a private key. They are protecting your money if someone is trying to decode the transaction or public key.
Only if you share the private key they will not protect. So making the transfer using their wallet, do not matter what is happening because you will receive the money because the transaction is guaranteed.
So Import the private key in Binance wallet, transfer the funds to onchain wallet and VOILA! You have the money in 10 min without any risk!

Thank you for information! I was reading about this many times, but now i need to prove you that the Binance method will work. So i will use the  Binance method when i will find something. I was not searching anything until now but now i have a challenge.

Let's say you are right and i do not have this information yet and i need to read more.
If someone is staying to steal, should have already the devices(1000+) ready and they have no ideea when someone will do the transaction or not. Even if they own or rent the devices and they have in standby, the money they spent for nothing are huge!!!
Let's say they crack in minutes before the transaction is made, there are multiple solutions without using MARA:
-create 1000 transactions to a good wallet from the puzzle
-make a sweep keys with another wallet
-go and make a payment on chain
-go and convert funds on chain to another coin
Even for that they can crack your wallet?

Anyway, if you go in binance wallet, and you have the identity verified, you can add the private key there and make the transaction. If anybody want to steal the money, you are covered by Binance system because is their wallet

So have fun!

Everybody is speaking about MARA, but is really safe?
You go on first page and say enter your transaction gex without any identification.
Even with this issue of unknowing what is happening when you submit, if everything is true about stealing, why they do not steal from everyone? There are milions of tranzactions every day.
If this was the case, nobody was using bitcoin anymore...

For 10 GPU 4090 i get 92000MK/s.
For 8 GPU 4090 i get 74000MK/s

Did anybody saw that almost on each search you get addresses that contain 9h, 9W, 9t?

Regarding the ones with comments that finally they discovered and be prepared, please don't give such comments because you are like little children discovered a candy for first time.

Many thanks for technical people who is sharing. On next post i will share a new solution ideea just with python script.

And to give a hint: is a formula based on the number of puzzle, the amount of BTC from each wallet and the TX number from each puzzle. This formula can be applied to all puzzles based on the information we know, including the 135+.

Please watch this video to see my theory.

https://m.youtube.com/shorts/-rxN_y5K9vA?si=PsxWaGWLpe9HoQlO

No, what you did is to calculate only on this puzzle. The main ideea is to think big, out of the box. Maybe 99% are laughing about this theory, but all music songs have behind math...sequence of numbers arranged in a specific order to hear something...

Is just a pattern that i saw about the song and i will come back soon and explain after i will test this theory. But from what i saw, all keys are based on a music score.
Anyway besides this i created a prediction tool that you enter the BTC address and is giving you the private key in hex(now do not think there is a trick and the key already exist behind). At the beginning it had 0.0008 accuracy and in 1 month i raised to 0.8 accuracy. I need to buy more NVME(~100 TB) in order to feed the program and let him generate the data it needs.

Hello,
I am new in this, but i have a question for everybody: The puzzle creator was fan of Freddie Mercury?
I discovered a patern that is matching a song of Freddie Mercury.