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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
by
fecell
on 16/07/2025, 16:40:50 UTC
🎯 REVISED P71 POSITIONING:
✅ Position:  77.3%  ( Success Probability 88.0% )
📍 Target Range: 0x7174 area
🔬 Improved Calibration: Enhanced mathematical modeling
📊 Confidence: Higher precision positioning
🎯 Search Strategy: COVERAGE deployment recommended
Reason for sharing this update:

"The mathematical positioning keeps evolving as I refine the φ-based calculations. This has higher success probability."

step count: 40000000
total bits: 135
range step: 544451787073501541541399371890829
range bits: 109
progress is loaded: 40000000/80000000/9315
solve...
  • [9699] [14:30:01]
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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
by
fecell
on 02/07/2025, 16:58:12 UTC
All numbers are binary, there's nothing to convert there, since that's what they already are. And every bit at every position has a 50% chance of being either 0 or 1
wrong!!! 40/60.
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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
by
fecell
on 02/07/2025, 16:45:43 UTC
Code:
from ecc import Ecc as CUDA_ECC
ecc = CUDA_ECC(pathdll)
print(ecc.get_public_key_by_private_key([x for x in range(1,10_000_000_000)]))

Python is a very convenient language for puzzle solve, with GPU option.
 Wink
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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
by
fecell
on 01/07/2025, 08:20:04 UTC
Did you know, that if the puzzle creator spent so much money so easily, how many bitcoins does he still have left? (rhetorically)
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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
by
fecell
on 01/06/2025, 15:03:45 UTC
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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
by
fecell
on 01/06/2025, 09:13:07 UTC
new idea for...

Code:
import numpy as np
from scipy.integrate import odeint
import matplotlib.pyplot as plt
import matplotlib.animation as animation
from matplotlib.patches import Circle

L1 = 1.0
L2 = 0.8
m1 = 1.0
m2 = 1.5
g = 9.8
k = 0.1

initial_state = np.radians([120.0, 0.0, -20.0, 0.0])

t = np.linspace(0, 20, 1000)

def equations(state, t):
    theta1, z1, theta2, z2 = state
   
    perturbation1 = k * np.sin(5*t) * np.cos(3*theta1)
    perturbation2 = k * np.cos(4*t) * np.sin(2*theta2)
   
    c = np.cos(theta1 - theta2)
    s = np.sin(theta1 - theta2)
   
    denominator = L1 * L2 * (m1 + m2*np.sin(theta1 - theta2)**2)
   
    dz1 = ((-g*(m1 + m2)*L2*np.sin(theta1) + m2*g*L2*np.sin(theta2)*c
           + m2*L2*z2**2*s + m2*L1*z1**2*s*c) / denominator) + perturbation1
   
    dz2 = ((-m2*g*L1*np.sin(theta2) + (m1 + m2)*g*L1*np.sin(theta1)*c
           - (m1 + m2)*L1*z1**2*s - m2*L2*z2**2*s*c) / denominator) + perturbation2
   
    dz1 -= 0.01 * z1
    dz2 -= 0.01 * z2
   
    return [z1, dz1, z2, dz2]

solution = odeint(equations, initial_state, t)
theta1 = solution[:, 0]
theta2 = solution[:, 2]

x1 = L1 * np.sin(theta1)
y1 = -L1 * np.cos(theta1)
x2 = x1 + L2 * np.sin(theta2)
y2 = y1 - L2 * np.cos(theta2)

fig, ax = plt.subplots(figsize=(8, 8))
ax.set_xlim(-(L1+L2+0.2), L1+L2+0.2)
ax.set_ylim(-(L1+L2+0.2), L1+L2+0.2)
ax.set_aspect('equal')
ax.grid()

line, = ax.plot([], [], 'o-', lw=2, color='black')
trace, = ax.plot([], [], '-', lw=1, color='red', alpha=0.5)
ball1 = Circle((0, 0), 0.05, fc='blue', zorder=3)
ball2 = Circle((0, 0), 0.05, fc='green', zorder=3)
ax.add_patch(ball1)
ax.add_patch(ball2)

history_x, history_y = [], []
max_history = 500

def init():
    line.set_data([], [])
    trace.set_data([], [])
    ball1.center = (0, 0)
    ball2.center = (0, 0)
    return line, trace, ball1, ball2

def animate(i):
    points_x = [0, x1[i], x2[i]]
    points_y = [0, y1[i], y2[i]]
   
    line.set_data(points_x, points_y)
    ball1.center = (x1[i], y1[i])
    ball2.center = (x2[i], y2[i])
   
    history_x.append(x2[i])
    history_y.append(y2[i])
    if len(history_x) > max_history:
        history_x.pop(0)
        history_y.pop(0)
    trace.set_data(history_x, history_y)
   
    return line, trace, ball1, ball2

ani = animation.FuncAnimation(
    fig, animate, frames=len(t),
    interval=1000/60, init_func=init, blit=True
)

plt.xlabel('X')
plt.ylabel('Y')
plt.tight_layout()
plt.show()

ps: like russian song ("carved garden"): https://www.youtube.com/watch?v=90KiaZWqOIg

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Re: == Bitcoin challenge transaction: ~1000 BTC total bounty to solvers! ==UPDATED==
by
fecell
on 28/05/2025, 11:23:53 UTC
In Case You Missed It
Puzzle #69 Found on 30-4-2025
0x0000000000000000000000000000000000000000000000101d83275fb2bc7e0c
I just save a link to Blockchain explorer and the wallet, so you see very quick when a puzzle is solved (-> funds = 0 Cheesy)
Blockchain explorer didnt show private key.
https://privatekeyfinder.io/bitcoin-puzzle/
this link show all puzzle's addresses too.
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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
by
fecell
on 28/05/2025, 02:05:00 UTC
Hey has the privatekeys.pw site been down all day for you guys too?
use https://privatekeyfinder.io/bitcoin-puzzle/
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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
by
fecell
on 19/05/2025, 11:31:32 UTC

At 300 MKeys/s?
I check around 5.316911983139664e+36//1000000000000000 in moment (for 2**0...2**256).
but this is not for cracking secp256k1, or puzzle 135, or all elliptic curves.
so I generally keep quiet. this is only for education and testing purposes.
hmm. weird stuff with math in y**2=x**3+7 arrived.
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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
by
fecell
on 15/05/2025, 07:01:59 UTC
Pay To Public Key

"outputs": [
    {
      "address": "1Lo1VC2YNkqELDNGHpsKDD8KEzbNKBjzpF",
      "pkscript": "41040000356cb2e0d0c0a0167693b14c338f548da20fea024a04449907140fa270ebff37ae70d00 db8137b5c60d9563b743b090f162f7bf1b51650d20cd7022d695dac",
      "value": 5000000000,
      "spent": false,
      "spender": null
    }
  ],

pkscript = public key
so it's a dead end.
it just picks some random coordinate in secp26k, and each transmission just increments X. but nobody (and the owner of 1Lo1VC2YNkqELDNGHpsKDD8KEzbNKBjzpF) will ever know the private key.
just look at X.. its constantly grow. this means scalar*G was not used to create PubKey, just increment X:
040000356cb2e0d0c0a0167693b14c338f548da20fea024a04449907140fa270ebff37ae70d00
04000136bd8d133189ca0e40334a05ac1ce1d33e992f8628a582ec6a27757d0338e1ec3c25631
040001c5a1d394656166be6c0d41219ed3bba0b2b4dd38d0c0f317b6ad0c491ffca489d30ae91
04000272b300286c7870642be993dd7189a7dd4f713ad133cb04a36f5560dd28ef9782ac421aa
040005929d4eb70647483f96782be615f7b72f89f02996621b0d792fd3edd20dc229a99dfe635
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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
by
fecell
on 14/05/2025, 14:02:23 UTC
You should add Satoshi's 34k public keys to your list, each one with 50BTC. Maybe someone can calculate how many RTX-5090's you'd need to crack just one of those wallets in 24 hours?  Wink
how pub keys was gotten, if no one out TX was?!
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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
by
fecell
on 14/05/2025, 14:00:47 UTC
You should add Satoshi's 34k public keys to your list, each one with 50BTC. Maybe someone can calculate how many RTX-5090's you'd need to crack just one of those wallets in 24 hours?  Wink
how pub keys was gotten, if no one TX was?!
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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
by
fecell
on 04/05/2025, 11:00:03 UTC
Did U know?
Quote
Oddly enough, all algorithms - Pollard, Floyd, Shanks - work the same way. The only difference is in the choice of step and interpretation of values.
Wink
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(Unknown Title)
by
fecell
on 02/05/2025, 10:04:37 UTC
It's pure statistics. But it would be stupid to make it public for obvious reasons. This has to be a private message. Grin
I completely agree.
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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
by
fecell
on 01/05/2025, 04:57:08 UTC
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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
by
fecell
on 01/05/2025, 04:35:17 UTC
whats happened?!
https://www.blockchain.com/en/explorer/addresses/btc/19YZECXj3SxEZMoUeJ1yiPsw8xANe7M7QR
6.9 BTC was reset to 0.70071362, TX are lost. Hm.
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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
by
fecell
on 27/04/2025, 03:07:15 UTC
Did U know...

Code:
G = 115792089237316195423570985008687907852837564279074904382605163141518161494338 * G

Wink
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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
by
fecell
on 24/04/2025, 12:56:26 UTC
Wat ?

Here is an example of an improved enumeration of points from 1 to 10. If we take the cost of one inversion as $1, then we save $4: starting from point 3, we make a step of 5 in the cycle, points 1,2,6,7 are formed using the calculated inversion for 4,5,9,10 respectively.

Code:
         $1                  $1        
---------+-------------------+---------
 $0      |      $1   $0      |      $1
 .-------+-------.   .-------+-------.
 |   $0  |  $1   |   |   $0  |  $1   |
 |   .---+---.   |   |   .---+---.   |
 |   |   |   |   |   |   |   |   |   |
 1   2   3   4   5   6   7   8   9   10
funny. but real life not so easy.

Quote
The wise man asked the king to pay him one grain of wheat for the first square on the chessboard, two for the second, four for the third, and so on, doubling the number of grains for each subsequent square.
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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
by
fecell
on 23/04/2025, 04:53:31 UTC
Did U know, 0.5G point has extremly low X coordinate  Roll Eyes
Code:
Qx: 0x00000000000000000000003b78ce563f89a0ed9414f5aa28ad0d96d6795f9c63
Qy: 0xc0c686408d517dfd67c2367651380d00d126e4229631fd03f8ff35eef1a61e3c
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Re: Bitcoin puzzle transaction ~32 BTC prize to who solves it
by
fecell
on 12/04/2025, 14:33:46 UTC
I probably figured out why every fifth public key was compromised by creator.
look at y^2=x^3+7 without mod p.
most every fifth value has a huge 'x' (pubkey) coordinate.
 Wink
good luck!