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For sale (all items timestamped w/username):
SOLD 1. 1995 Isle of Man Bimetallic Platinum and Gold Angel and Noble Coins: 0.12BTC SOLD
This 2-coin set features a bimetallic Angel and Noble coin that contains Platinum and Gold.
Contains 1/4 oz .9999 Gold and 1/4 oz of .9995 fine Platinum.
Set comes in box with numbered plaque.
2. 2009 Isle of Man 1/10 angel and 1/4 angel Gold/silver bimetallic set NGC pf69: 0.062BTC total on both
1/10 oz proof platinum Canadian Bison with box and COA: 0.017BTC
Escrow accepted and preferred. Ships USPS to all 50 US states and shipping is fast and free. No international unless we can really work something out.
Message me with any questions.
Thanks!
Jajorda23
SOLD 1. 1995 Isle of Man Bimetallic Platinum and Gold Angel and Noble Coins: 0.12BTC SOLD
This 2-coin set features a bimetallic Angel and Noble coin that contains Platinum and Gold.
Contains 1/4 oz .9999 Gold and 1/4 oz of .9995 fine Platinum.
Set comes in box with numbered plaque.
2. 2009 Isle of Man 1/10 angel and 1/4 angel Gold/silver bimetallic set NGC pf69: 0.062BTC total on both
1/10 oz proof platinum Canadian Bison with box and COA: 0.017BTC
Escrow accepted and preferred. Ships USPS to all 50 US states and shipping is fast and free. No international unless we can really work something out.
Message me with any questions.
Thanks!
Jajorda23
Aren't these on the scam and breached coin list? 
0.05 btc seems pretty high?
0.05 btc seems pretty high?Youre correct and you might be right on the price! Still collectible to some.
For auction is a 2014 Microsoul 0.01BTC in capsule.
For information on Microsoul, there are plenty of forum posts on the topic.
STARTING BID PER LOT: 0.05BTC
MINIMUM BID INCREMENT: 0.001BTC
END TIME: SUNDAY AUGUST 4th, 2019, 18:00:00 EST (New York Time)
SNIPE: Any bid made in last 5 minutes will extend the auction 5 minutes beyond the ending time, and if within those 5 extended minutes, a new bid is made, 5 minutes will be added to the auction from the time of that bid.
SHIPPING: Based on location and preference
PAYMENT: ONLY SEND TO THE ADDRESS IN MY PROFILE (escrow fine as well)
Happy auctioning!
For information on Microsoul, there are plenty of forum posts on the topic.
STARTING BID PER LOT: 0.05BTC
MINIMUM BID INCREMENT: 0.001BTC
END TIME: SUNDAY AUGUST 4th, 2019, 18:00:00 EST (New York Time)
SNIPE: Any bid made in last 5 minutes will extend the auction 5 minutes beyond the ending time, and if within those 5 extended minutes, a new bid is made, 5 minutes will be added to the auction from the time of that bid.
SHIPPING: Based on location and preference
PAYMENT: ONLY SEND TO THE ADDRESS IN MY PROFILE (escrow fine as well)
Happy auctioning!
Ive been looking at this a different way. What if the questions anagram solution isnt really leading to that being the private key. What if it is a guide toward the key? There are words like obtain and key that can be extracted. Similar bitcoin related words like hash and satohash, combo name(s) etc. I wonder..
So...
You know how Watashi linked into a github repo by movedon2otherthings that included code for a tool called Satohash?
Yeah...the code didn't work.
BUT I FIXED IT!
There were absolutely no declarations in the header file to match the definitions.
https://github.com/jajorda2/satohash
You just need to compile in terminal:
You can then follow the example instructions in the readme.md.
DISCLAIMER
I do not know if this has anything to do with the puzzle. I've converted a number of phrases this way into sha256 private keys, converted them to WIF, and no glorious "179..."
Enjoy
You know how Watashi linked into a github repo by movedon2otherthings that included code for a tool called Satohash?
Yeah...the code didn't work.
BUT I FIXED IT!
There were absolutely no declarations in the header file to match the definitions.
https://github.com/jajorda2/satohash
You just need to compile in terminal:
Code:
gcc satohash.c hash.h -o run
You can then follow the example instructions in the readme.md.
Code:
./run
to execute whatever you're trying to do.DISCLAIMER
I do not know if this has anything to do with the puzzle. I've converted a number of phrases this way into sha256 private keys, converted them to WIF, and no glorious "179..."
Enjoy
To further the connection between Blockladder and watashi-kokoto:
They both have yahoo.co.jp addresses if that means anything to you. Blockladders PGP sig on github reveals his email.
Maybe they're both japanese?
They both have yahoo.co.jp addresses if that means anything to you. Blockladders PGP sig on github reveals his email.
Maybe they're both japanese?
blockladder / watashi-kokoto GitHub connection
Looking at blockladder's "project pr" forks, there is a user called bakujo. Not much by itself, but they are following one and only person: our watashikokoto.
blockladder and watashi are perhaps close friends.
Looking at blockladder's "project pr" forks, there is a user called bakujo. Not much by itself, but they are following one and only person: our watashikokoto.
blockladder and watashi are perhaps close friends.
https://bitcointalk.org/index.php?topic=2044123.0
Satohash seems like a commonly followed repository between them all on Github.
I mean, there are several possibilities here. It could be that OP expects us to input a 32 (i.e. 32 bytes = 256bit) char english worded answer, convert it to private key through some algorithm like the one in the link.
It could also be that OP is simply referring to an 8 word 32 char answer to be input into a brainwallet checker right away.
It could be that the answer to the question leads to a second clue that will contain the private key.
Who knows?
Forget using the code in the repository. There's no .cpp file (which I am not skilled enough to compose) so gcc won't compile it--the header file contains undefined references.
blockladder / watashi-kokoto GitHub connection
Looking at blockladder's "project pr" forks, there is a user called bakujo. Not much by itself, but they are following one and only person: our watashikokoto.
blockladder and watashi are perhaps close friends.
Looking at blockladder's "project pr" forks, there is a user called bakujo. Not much by itself, but they are following one and only person: our watashikokoto.
blockladder and watashi are perhaps close friends.
https://bitcointalk.org/index.php?topic=2044123.0
Satohash seems like a commonly followed repository between them all on Github.
Totally hear you, Cassius. Here's my method, though.
Here are the steps...basically...and of course I could be wrong but take it with a grain of salt.
1. We know Natasha Otomoski is equivalent to Satoshi Nakamoto. That's very obvious.
2. To obtain NATASHAOTOMOSKI=SATOSHINAKAMOTO we know how the letters have to be arranged. Its exactly what Watashi-Kokoto said (whether he's the OP or not doesn't matter).
3. So numbering 1-15, we get "5, 2, 3, 8, 13, 6, 15, 1, 4, 14, 7, 11, 10, 9, 12"
4. Now let's use an alphabet:
5. A=1, B=2, C=3 D=4, E=5, etc..
6. Now rearrange the alphabet using step 3:
7. "E B C H M F O A D N G K J I L"
8. This is the decryption key.
9. (8,2,3,9,1,6,11,4,14,13,12,15,5,10,7)⇔(5,2,3,8,13,6,15,1,4,14,7,11,10,9,12)-1
SUMMARY
What I'm saying is that we know the NATASHA --> SATOSHI is a permutation. So, why wouldn't the rest of the phrase be as well? I could be totally in left-field, for sure. But this is my best assumption.
Here are the steps...basically...and of course I could be wrong but take it with a grain of salt.
1. We know Natasha Otomoski is equivalent to Satoshi Nakamoto. That's very obvious.
2. To obtain NATASHAOTOMOSKI=SATOSHINAKAMOTO we know how the letters have to be arranged. Its exactly what Watashi-Kokoto said (whether he's the OP or not doesn't matter).
3. So numbering 1-15, we get "5, 2, 3, 8, 13, 6, 15, 1, 4, 14, 7, 11, 10, 9, 12"
4. Now let's use an alphabet:
5. A=1, B=2, C=3 D=4, E=5, etc..
6. Now rearrange the alphabet using step 3:
7. "E B C H M F O A D N G K J I L"
8. This is the decryption key.
9. (8,2,3,9,1,6,11,4,14,13,12,15,5,10,7)⇔(5,2,3,8,13,6,15,1,4,14,7,11,10,9,12)-1
SUMMARY
What I'm saying is that we know the NATASHA --> SATOSHI is a permutation. So, why wouldn't the rest of the phrase be as well? I could be totally in left-field, for sure. But this is my best assumption.
So I'm tired of trying this weekend.
Here's what I can't figure out. If the remainder of the phrase is also a permutation cipher, how do we extend this key? It does NOT work for the entire phrase.
If we can figure out the key for the WHOLE phrase, that'll give us the full translation for whatever the ?.txt file might be.
Someone skilled in decoding might have some ideas. Let's keep this going
edit:
Quote
NATASHAOTOMOSKI --> SATOSHINAKAMOTO
is a permutation cipher. I've known this for a while. Here's the key:Quote
e b c h m f o a d n g k j i l
Here's what I can't figure out. If the remainder of the phrase is also a permutation cipher, how do we extend this key? It does NOT work for the entire phrase.
If we can figure out the key for the WHOLE phrase, that'll give us the full translation for whatever the ?.txt file might be.
Someone skilled in decoding might have some ideas. Let's keep this going
edit:
Quote
E B C H M F O A D N G K J I L
5 2 3 8 13 6 15 1 4 14 7 11 10 9 12
S A T O S H I N A K A M O T O
5 2 3 8 13 6 15 1 4 14 7 11 10 9 12
S A T O S H I N A K A M O T O
How can you be sure this is a permutation cipher? It's equally possible the 'key' is just the result of a random anagram, right?
https://crypto.interactive-maths.com/permutation-cipher.html
Ill type a detailed response after breakfast. You can use this permutation cipher silver to check the key. Type natashaotomoski in the bottom box, the key where it says key, and hit decrypt.
So I'm tired of trying this weekend.
Here's what I can't figure out. If the remainder of the phrase is also a permutation cipher, how do we extend this key? It does NOT work for the entire phrase.
If we can figure out the key for the WHOLE phrase, that'll give us the full translation for whatever the ?.txt file might be.
Someone skilled in decoding might have some ideas. Let's keep this going
edit:
Quote
NATASHAOTOMOSKI --> SATOSHINAKAMOTO
is a permutation cipher. I've known this for a while. Here's the key:Quote
e b c h m f o a d n g k j i l
Here's what I can't figure out. If the remainder of the phrase is also a permutation cipher, how do we extend this key? It does NOT work for the entire phrase.
If we can figure out the key for the WHOLE phrase, that'll give us the full translation for whatever the ?.txt file might be.
Someone skilled in decoding might have some ideas. Let's keep this going
edit:
Quote
E B C H M F O A D N G K J I L
5 2 3 8 13 6 15 1 4 14 7 11 10 9 12
S A T O S H I N A K A M O T O
5 2 3 8 13 6 15 1 4 14 7 11 10 9 12
S A T O S H I N A K A M O T O
As kind of a quick guess today, I thought to myself "Maybe Blockladder was a hitchhiker's guide to the galaxy fan". After all, 21*2=42, the answer to life, the universe, and everything. Turns out in ISO/IEC 14519-2001/ IEEE Std 1003.5-1999, IEEE Standard for Information Technology POSIX(R) Ada Language Interfaces Part 1: Binding for System Application Program Interface (API), "The Choice Of The Value 42 Is Arbitrary", a phrase which, when spaces are removed, = 8 words and 32 characters. I changed 42 to 21 and no dice. "TheChoiceOfTheValue21IsArbitrary" doesn't work as a brainwallet or through my Python hashing method. *SHRUG*
Just thought you all might get some out-of-the-box inspiration!
Oh and *edit* if that wasn't enough THE SUM OF ALL FACTORS OF 21 IS 32! Not that that probably means anything.
Just thought you all might get some out-of-the-box inspiration!
Oh and *edit* if that wasn't enough THE SUM OF ALL FACTORS OF 21 IS 32! Not that that probably means anything.
Thanks for the python script...
However I cannot do the imports somehow,..?
I get :
----------------
Traceback (most recent call last):
File "C:\Python\GPuzzelky.py", line 2, in
from bitcointools import *
ModuleNotFoundError: No module named 'bitcointools'
----------------
Any help is appreciated?
(i tried this : TheCombOfWatashiKokotoHas21Teeth and variations... no luck so far :-))
However I cannot do the imports somehow,..?
I get :
----------------
Traceback (most recent call last):
File "C:\Python\GPuzzelky.py", line 2, in
from bitcointools import *
ModuleNotFoundError: No module named 'bitcointools'
----------------
Any help is appreciated?
(i tried this : TheCombOfWatashiKokotoHas21Teeth and variations... no luck so far :-))
pip install bitcointools
*OR*
python2.7 pip install bitcointools
You MUST have pip installed FYI
Considering that:
1. watashi-kokoto was the first one to reply to this thread:
2. Blockladder has 2 deleted posts, both were in the threads created by guess who? Correct, watashi-kokoto.
3. Based on posts history both accounts were active at approximately the same time.
There is a very high probability that it's the same person.
1. watashi-kokoto was the first one to reply to this thread:
Obviously she isn't him, but
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
S A T O S H I N A K A M O T O
8 2 3 9 1 6 11 4 14 13 12 15 5 10 7
N A T A S H A O T O M O S K I
who do you all think is she anyways?
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
S A T O S H I N A K A M O T O
8 2 3 9 1 6 11 4 14 13 12 15 5 10 7
N A T A S H A O T O M O S K I
who do you all think is she anyways?
2. Blockladder has 2 deleted posts, both were in the threads created by guess who? Correct, watashi-kokoto.
3. Based on posts history both accounts were active at approximately the same time.
There is a very high probability that it's the same person.
That was my thought exactly. Watashi has a post about buying accounts as well. Can't help but wonder if blockladder is a bought account. Anywho, might as well try the anagram solution.
I'm offering to the community a full-blown Python 2.7 script to transform 32 character plain-text to priv/pub keys. The code is below:
Code:
import binascii, hashlib, base58
from bitcointools import *
from electrum import Network
def priv2addr(priv):
pub = privtopub(priv)
addr = pubtoaddr(pub)
return (addr)
# Step 1: here we have the private key
#private_key_static = "0000000000000000000000000000000000000000000000000000000000000002"
private_key_static = binascii.hexlify("InsertPlainTextPhraseHere32Chara")
print (private_key_static)
#private_key_static = ("Because it was an educated guess")
# Step 2: let's add 80 in front of it
extended_key = "80"+private_key_static.strip()
# Step 3: first SHA-256
first_sha256 = hashlib.sha256(binascii.unhexlify(extended_key)).hexdigest()
# Step 4: second SHA-256
second_sha256 = hashlib.sha256(binascii.unhexlify(first_sha256)).hexdigest()
# Step 5-6: add checksum to end of extended key
final_key = extended_key+second_sha256[:8]
print (final_key)
# Step 7: finally the Wallet Import Format is the base 58 encode of final_key
WIF = base58.b58encode(binascii.unhexlify(final_key))
print (WIF)
print (priv2addr(WIF))
from bitcointools import *
from electrum import Network
def priv2addr(priv):
pub = privtopub(priv)
addr = pubtoaddr(pub)
return (addr)
# Step 1: here we have the private key
#private_key_static = "0000000000000000000000000000000000000000000000000000000000000002"
private_key_static = binascii.hexlify("InsertPlainTextPhraseHere32Chara")
print (private_key_static)
#private_key_static = ("Because it was an educated guess")
# Step 2: let's add 80 in front of it
extended_key = "80"+private_key_static.strip()
# Step 3: first SHA-256
first_sha256 = hashlib.sha256(binascii.unhexlify(extended_key)).hexdigest()
# Step 4: second SHA-256
second_sha256 = hashlib.sha256(binascii.unhexlify(first_sha256)).hexdigest()
# Step 5-6: add checksum to end of extended key
final_key = extended_key+second_sha256[:8]
print (final_key)
# Step 7: finally the Wallet Import Format is the base 58 encode of final_key
WIF = base58.b58encode(binascii.unhexlify(final_key))
print (WIF)
print (priv2addr(WIF))
Re: [24HR AUCTION] Platinum and Silver Bitcoin Penny Lot (GOLD JUST ADDED)
1. .04
This bid was 5min too late as far as Im aware.
@jajorda23 can you confirm?
The bid at 6:50 est should add 15 minutes from 7pm est. any bid in the last 15 adds 15 to the end. So if no bids are made 15 minutes after 7:15, bidding ends. Otherwise any further bids add an additional 15
