Hi Stephan,
I'd prefer just to talk about the technical stuff but I'll leave this here as no one has really said what I want to. I'm a little surprised at some of the interpretations people have had about what the pricing scheme would be for the advanced trade bot you just released. It seems fair to me, and in line with what you'd posted. The only thing I would be concerned about is if I wished to solely use the simple trading bot, that from now you may not support it as much as you had in the past.
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I posted a few pages back regarding the fee overcome, I've been busy since then but managed to have a look at the update you put out (9.12 I think), but I still don't think it's right. For BTCe, with % fees, the amount that the price has to raise or drop in order to 'break even' should only be a function of the fee, and the buy/sell prices. The amount I am trading with does not matter, I can't think how to express this elegantly with maths, but I'll have a go.
I start with $1000. I buy bitcoins on BTCe at $800/BTC. With the 0.2% fee I will receive $1000/($830/BTC)*(1-0.002) = 1.2475 BTC. (Eqn. 1)
In order to break even I must sell these bitcoins for 1.2475 BTC * ( $X / BTC ) * (1-0.002) = $1000. (Eqn. 2)
Solving for X gives $1000 / 1.2475 / (1-0.002) = $803.209... the amount which I must sell for in order to pay for the fees (and make no profit).
If you follow the above with different starting amounts you will get the same selling price.
Mathematically if you substitute the amount of bitcoins purchased from Eqn. 2 into Eqn. one (after rearranging Eqn. 2) we have:
$1000/($830/BTC)*(1-0.002)=$1000/($X/BTC)/(1-0.002)
dividing by the starting amount ($1000), and rearranging for the sell price ($X/BTC), we have:
$X/BTC = $830/BTC / (1-0.002) / (1-0.002) or $X/BTC = $830/BTC / (1-0.002)^2
or, more simply,
sell price = buy price / (0.998^2)
which is not a function of the trade amount.
I think that explanation is about 10x longer than it needed to be, and I feel like I'm stating the obvious, but maybe it helped someone haha.
Is that your understanding too Stephan? It appears to me the tradebot fee overcome is based on the amount you enter to trade with.