Quote from: jettico on January 30, 2014, 08:04:42 PM

Now imagine that you throw a dice with numbers from 1 to 6 and your opponent throws a semi-dice with three possible values from 1 to 3.

this analogy doesn't match forging properly, as the second dice(1-3) can't be treated uniform distribution. Instead, the p(1) = 1/6, p(2) = 1/6, p(3) = 2/3 which should also includes the implicitly removed p(4),p(5),p(6) in your analogy.
in this way, the ratio should be 2 rather than 3.

edit: if 100k divided into 100*1k, 100*p(1k gen Block) will be slightly lower than p(100k gen Block) as generation mutual exclusion

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