Quote from: Sha256explorer on April 20, 2023, 08:56:20 PM

I made some small improvements:
1) I called the noncework function 2**32 times, not just 10 million million times
2) every time i called the noncework function, i passed the loop value k, using that number as the nounce and not a random number

I could also have used the time parameter, another 5000 or 6000 times cycle, so that the root merkle only resets once every 5000*2**32. In that case, if we had a 100 TH/S asic instead of a CPU, it would have to recalculate the nounce every 4 or 5 seconds, if I'm not mistaken.

Code:

# omitted for brevity

# use this loop if you want to do a speed test with only 1 million rounds
start = time.time()
for k in range(1000000):
noncework(k)
end = time.time()
print(end - start)
# about 42.5
'''
# use this loop if you want to try all the nounce with 2**32 rounds
for k in range(2**32):
noncework(k)
'''
print("Finished nounce. Regaining Information.")
sock.close()
main()

main()

I'm interested to understand why you chose (2**32) as the target for noncework. Given the end-start times when I tried your script, the noncework function takes around 2.5 hours. In that time, it's almost certain that a block would be found and you'd be looking at coinbase etc information from a non-current block. Am I wrong here, or should you be regaining information much sooner?

Also, can you explain the advantage of noncework(k) instead of noncework() ? Thanks!

I'm trying to optimize the script as a bit of fun, given I'll never mine a block, my goal is to improve my Mh/s figure as much as possible and learn more about the technical background underpinning mining.

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