Post
Topic
Board Gambling
Re: Challenge: What's the best way to win 1 BTC with 1 BTC?
by
Coef
on 18/10/2015, 19:28:30 UTC
Hmm just thought about it, has OP yet paid the prize he has claimed to pay to the best method or is he still searching for more strats?

He already paid, and it's likely we have the best strategy already.

It is dangerous to jump to the conclusion quickly. Tongue


leading to a 49.64716% chance of winning.

you have a 49.64812% chance of winning.

chance of winning =  100 * (1 - ((100 - 1.0664) / 100) ** 64) = 49.649475445976265%

With 1 btc, I should be able to make a total of 3430 x4950 (ie 0.02%) bets, each with a bet size of roundup((2-balance)/4949) to the nearest satoshi that could bring my balance to slightly over 2 btc if the bet wins. After that, I will have 0.00027093 left and a final x9900 (ie 0.01%) bet can be made which could bring my balance to 2.682207 btc.
Check http://pastebin.com/TL7xLTx4 for the complete betting sequence in details in CSV format.

Chance of winning = 1 - ((1 - 0.02%) ^ 3430 * (1 - 0.01%)) = 49.649851332%.


Or, I should be able to make a total of 2287 x3300 (ie 0.03%) bets, each with a bet size of roundup((2-balance)/3299) to the nearest satoshi.
Check http://pastebin.com/Je5ujHH9 for the complete betting sequence in details in CSV format.

Chance of winning = 1 - ((1 - 0.03%) ^ 2287) = 49.651579392%


Yeah, but you also said:

added 0.1 to blockage's account. If someone can beat his solution, I'll give them 0.1 as well.

Ahh touché, forgot I wrote that.

I notice the word "them" in the quote. Do I get 0.1 btc for beating dooglus' solution? Tongue