How about this:
bet 0.01088928 BTC @ 1.0664%
if you win, your profit is ((99 / 1.0664) - 1) * 0.01088928 = 1.00002474 BTC
if not, martingale at the same chance of winning, to keep the same net profit
you can afford 64 bets
chance of winning = 100 * (1 - ((100 - 1.0664) / 100) ** 64) = 49.649475445976265%
Edit: here are the 64 bets:
chance multiplier
1.0664% 92.83570893x
bet # stake total lost profit
----- ---------- ----------- ----------
1 0.01088902 1.00000087
2 0.01100759 0.01088902 1.00000081
3 0.01112745 0.02189661 1.00000065
I have bolded the line "if not, martingale at the same chance of winning, to keep the same net profit" because I am confused, you say to do a martingale but the second bet should be 0.02177804 not 0.01100759 like you listed, it also doesn't double your other bets in the 64 bet run. If you are doubling your bet using the martingale system and keeping the same chance of winning, it is not possible to have 64 bets.
He is not doubling the bet, because he is not making x2 bet but x92.8357 bet. At that high multiplier, a small increase in the bet size is enough to have a profit (if the bet wins) big enough to bring total net profit to 1+ btc.