Quote from: ndnhc on January 08, 2016, 07:39:04 AM

(Odds of a single roll)^{(Number of consecutive rolls)} x 100

So, you are rolling >49.9999 twice,
Chances of winning both are 0.50² x 100 = 25%

This is correct, but perhaps a little hard to understand.

To give a simple example, if you toss a coin 3 times, the odds of getting 'heads' all three times is 1 in 2*2*2 = 1 in 8.

You can see this by listing all the different results you could get:

HHH
HHT
HTH
HTT
THH
THT
TTH
TTT

There are 8 different combinations. They are all equally likely. Each of them is a 1-in-8 chance.

So in general, if you have a chance 'c' of winning, and you play 'n' times, the chance of you winning all 'n' of your games is c*c*...*c where there are 'n' c's in the product.

That's also known as c^n, or "c to the power n".

For the coin-toss example, c is 0.5 and n is 3, so the overall chance is 0.5^3 = 0.5*0.5*0.5 = 0.125 = 1/8