Quote from: valiz on January 19, 2016, 02:36:29 PM

Quote from: sAt0sHiFanClub on January 19, 2016, 02:03:22 PM

Quote from: valiz on January 19, 2016, 08:59:02 AM

Quote from: valiz on January 19, 2016, 08:54:39 AM

Obviously, running your code does not always end up with "segmentation fault", it is only a possibility.

Code:

int main()
{
   [b]int array[10]; [/b]
   array[11] = 0;
   printf("stick with core\n");
}

Oops, I was wrong. Because you put the "array" array on the stack, there are no chances for "segmentation fault".

Peter TRoll 'developer' #REKT

Cheesy

The array is neither static nor in a function, so its not on the stack. More likely ( dependent on your setup) its pre-allocated in the programs data section.
The fact that you dont core any time is down to blind luck.

int main() { ... } is not a function?

Look again!

Code:

(gdb) run
Starting program: /home/valiz/petertroll

Breakpoint 1, main () at petertroll.c:6
6 array[11] = 0;
(gdb) info registers rsp
rsp 0x7fffffffe2b0 0x7fffffffe2b0
(gdb) print &array[11]
$2 = (int *) 0x7fffffffe2dc
(gdb) l
1 #include
2
3 int main()
4 {
5 int array[10];
6 array[11] = 0;
7 printf("stick with core\n");
8 }
9

you are correct. for some reason i didnt see that...