It would definitely be bullet #2 that hit the glass first... followed by bullet #3 and last was bullet #1. The reasoning being that #2 doesn't have any cracks that are "stopped" by existing cracks, #3 only has a crack stopped by cracks from #2, and #1 has cracks that are stopped by both #2 and #3.
That was a pretty easy one compared to the maths involved with the probabilities of dying in games of Russian roulette

Hi there!
Here is the challenge to test you knowledge of physics. Imagine you are climbing mountain and see as the plane passes near by. Meanwhile in plane two guys decide to play russian roulette and one of them triggers pistol to shoot the bullet in the opposite direction to the plane's movement trajectory. The initial bullet's speed is equal to the plane's speed.
QUESTION:What will happen to the bullet in climber's point of view? Would it stay with climber or fly in any direction?
if i am not mistaken it is called relative speed in English.
it means anything that is inside of a moving object has the same speed as the moving object so the speed of the bullet (Vib) is equal to speed of place (Vp). lets take that direction +
Vib = Vp
and when it is shot it gains another speed from shooting (Vfb) which is the opposite way (-) and equal to Vp again
Vfb = -Vp
so the total speed from the point of view of someone outside is:
Vtotal = Vfb + Vib = 0
meaning it will stay still from climber's POV
You are correct! But don't celebrate, we got some serious challenge for you.
Here is story like puzzle. In order to find out the truth you can ask any questions, and we will answer them as "Yes", "No" or "Doesn't matter". Here we go: one guy came to the saloon and asked the bartender for a glass of water. After drinking the water he asked bartender for another glass of water. The bartender didn't give the second one, instead he pulled out the revolver and shot at the ceiling. The guy left the saloon, seemed to be satisfied.
QUESTION: What happened?