Quote from: Crypto_Man1212 on July 01, 2019, 11:18:11 AM

So it should have been 0.01 * 4823 * 2?

96.46 ETH?

Then Ethex will go bankrupt at some point, because they're offering a 6-match jackpot that's too big?

If one believes that Birthday Paradox is applicable for Ethereum block hashes calculation algorithm, than you should use 0.06 instead of 0.01 in your calculation. To hit the Superprize you need to place a bet on 6 symbols, and there is a 0.01 ETH minimum for each symbol. If you not believe in Birthday Paradoc, you can calculate probability like 16^6, but the lottery history shows that any of this method doesn't make sense as the event of hitting jackpot can happen anytime. I.e. if in theory, there are 4k or 16 mln of combinations, but someone guesses the winning number on 100-th ticket, does it matter how many not-winning combinations left?

What we have done internally some time ago: we have checked equiprobability of symbols in Ethereum block hashes algorithm. Are Ethereum block hashes random enough to build gambling on it? We have scanned the Ethereum blockchain from the very first block to the very last one and calculated how many times each symbol has been met on each position of block hash. Ill leave this table here with no comments, to let you better understand how does the hashing algorithm works. It was made on block #7482000. You can decide which symbols or symbol groups (letters, numbers, odd, even) meet more often then others.

Thanks for your interest!