Quote from: Devicore on September 29, 2019, 11:32:41 PM

Quote from: st0ffl on September 29, 2019, 12:15:27 AM

Hi there,
i always thought the puzzle transaction was made by LBC, actually came here cause i saw some publickeys where revealed.
Congrats to #105! Seems like 57fe is winning the race.
Can we expect from 57fe and j2002ba2 that they share their scripts involving GPU ECPoint math when #110 or #115 is found?

I'm impressed how fast the kangaroo method is, tested the python script from 57fe, the modified multicore from Telariust and read BurtW c#.
As a c# developer i was playing a lot with eliptic curve points, when i wanted to learn about bitcoin and about it's security.
Back then i never thought about the the security when you would know that a public key is in a specific space...

I developed a method the last day which is easy to implement within your scripts and halfs the searchtime per space.
Looking forward to post it in BurtW's thread later if somebody is interested.
if the table from j2002ba2 is correct using 4x V100:
#110 > 90 days > 45 days
#115 > 1 year 147 days > 256 days

What i don't understand is why the creator of the puzzle revealed the publickeys to +5 from 2^160...
Correctly there should be 161 to 255 also rewarded when dealing with such.

Yes I am very interested about what BurtW and Telariust are doing too, that would be really interesting to see your method since without GPU, the best key/s on Pollard Rho Kangaroo are not more than 450k/s on CPU.. It's pretty good in fact but ridiculous if we compare it to GPU

As a C# developer have you tried to wrote your own GPU script ? Grin

By the way anybody know what theses values means exactly if we want to find the #110 on this Pollard Rho GPU script https://github.com/twjvdhorst/Parallel-Pollard-Rho/? What do we have to put instead of the "1" to make it work ?

Here's the cmd :

Code:

Please give the modulus (p).
1
Please give the generator (g).
1
Please give the order of the generator (q).
1
Please give the element (y).
1
What value k for the special point condition would you like to use?
1

This is to solve g^x = y where g is a prime order q ...