Quote from: philipma1957 on March 14, 2020, 04:49:08 PM

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Wow man, I appreciate your detailed instructions and help. Now I got full guide how to replace APW8) Can easily send your text to my techs and they will deal with it. Thank you so much.

Quote from: mikeywith on March 14, 2020, 07:52:07 PM

The APW8 that fits both T15 and S15 has an output voltage of 16.32V to 20.04V, and it costs about $100+ shipping, money wise I don't think it makes any sense to pay about 130-150 USD just to revive an old miner like the T15, it only does 23TH and consumes a good 1500-1600 watts, but that's the OP's call to make.

In my humble experience with these PSUs that Bitmain make, they are quite robust IMO, their PSUs have a lot more quality than the miners themselves, and I think I can say that at least 7-8 times out of 10 it's only a matter of PSU's fan replacement, and since you mentioned "several PSUs" I can only think that quite a good number of them only need a new fan, and those fans go for pretty cheap like $5-10, it's pretty easy to swap the PSU fan, you just need a screwdriver and a working PSU to test with.

I would love to know that the problem is only with fans. That way we can replace them quickly and save money. Thanks for the hint. We will check fans.

Quote from: lightfoot on March 15, 2020, 01:27:26 PM

Probably the best move after you've checked to see if the fans on the supplies are good and if swapping the supply makes a difference. Blown power supplies are usually caused by FET/IGBT issues and wind up blowing the small fuse on the AC end of the supply. If new ones are .02 btc I'd say go that way first.

Antminer boards tend not to short out the whole supply line, what usually happens is a chip goes bad but since it's one chip in 64/80 it just raises the voltage slightly on the rest of the chips and shuts down the board because the clock and spi signals don't flow through. You can quickly check by disconnecting the boards from the supply and see if it works. If it does check each board's power connections with a meter looking for 0 ohm resistance.

Ok, got it. Thank you, man! I appreciate it.