Quote from: brainless on May 30, 2020, 09:42:14 PM

Congrates to winner

giving you new thinking level for 115, from my previous research, some friends here tested but hard for them to believe earlier, just for information

check my 2048 pubkeys list
https://anonfiles.com/a750taA8n6/100bit_txt dated November 09, 2019, 06:35:23 PM
refrence
https://bitcointalk.org/index.php?topic=1306983.msg53030914#msg53030914

privatekey 110
hex: 35c0d7234df7deb0f20cf7062444
hex: 00000000000000000000000000000000000035c0d7234df7deb0f20cf7062444
dec: 1090246098153987172547740458951748 / 1024
dec: 1064693455228503098191152791945.06640625
hex: D7035C8D37DF7AC3C833DC189
pubkey: 03bb788bea10bedfc4f32aee0f542fc9a0749b5db72a8b094cbbad9fde366f6fa4

hex: D7035C8D37DF7AC3C833DC188
pubkey: 02f2c172df4c4553891bd3c5e8a668a8fd5f5a46d0bc6b109649507180011301ac

check my created 100 bit 02f2...301ac and 03bb788... 6fa4 listed in 2048 corresponding keys to 110 puzzle

@brainless

The solution set to your list is [(110_bit_private_key - 2i)/(1024)] modulo (secp256k1_group_order). This adds no new information to help solve the problem.