Quote from: saif92 on March 03, 2014, 04:30:14 PM

Quote from: deisik on March 03, 2014, 06:28:25 AM

Quote from: Carlos L. on March 02, 2014, 10:31:48 PM

With 2889 referrals, I find it odd that I've never gotten a 50% commission from a 0.22500000 BTC payout (10000 lucky number).

You are not the only one (though your referrals number is really astonishing, lol)... Grin

he is one of best marketing person on this forum won many referrals competitions already on TF chating site

How does he do it? What are his technics?

Quote from: Luror on March 03, 2014, 03:27:06 PM

Quote from: Carlos L. on March 02, 2014, 10:31:48 PM

With 2889 referrals, I find it odd that I've never gotten a 50% commission from a 0.22500000 BTC payout (10000 lucky number).

I'm in doubts the probability of rolling "10000" is 0.0001 with current algorithm, it would be interesting if someone would do an independent test (run an implementation of current algorithm 1,000,000 times, look at the amount of 10000's).

upd Ok, I looked at algorithm closer, and if everything is properly randomized, we can calculate the probability theoretically:

"3. The first 8 characters of the hex string are taken and converted to a decimal.
4. This decimal is then divided by 429496.7295 and rounded up to the nearest whole number.
5. This whole number is used as your roll, with the maximum possible value being 10,000."

We have hex strings from "00000000" to "ffffffff" (0 to 4294967295), 4294967296 in total. "ffffffff" converts to 4294967295/429496.7295 = 10000.

The biggest number which will be rounded to 10000 is 9999.5, back converting it (*429496.7295), we'll get 4294752546.63525.

So the numbers from the interval [4294752547, 4294967295] will be converted to "10000", the quantity of them = 4294967295-4294752547+1 = 214749.

The probability of getting "10000" = 214749/4294967296 = 0.00005000014789402484893798828125 (~ 1/20000)

P.S. After 40,000 rolls one should get 86% probability of rolling "10000" at least once

(proof: https://www.wolframalpha.com/input/?i=1-%281-0.00005000014789402484893798828125%29^40000)

I think it is way smaller than 1/20,000 if you look at the prices it doesn't add up

1,000,000 plays should have 50 winners if there was 1/20,000 to win 0.225 so 10BTC awarded