Quote from: PupTentacle on January 05, 2022, 11:51:50 PM

<snip
As Spock would say "Interesting".

So if I read that right, if PD is divorced from the master/slave (by supplying power from say a barrel connector) one could use the 4 wire USB 3.0 master/slave data protocol & achieve a higher data rate than USB 2.0. That would also allow for higher PD than 100W. Effectively limited only by the current handling of the barrel connector.

This makes sense as many USB 3.0 to SATAIII adapters have external wall warts to supply power to the SATA power port.

Did I glean that correctly?
Or am I all FUBAR & in need to re-read that reference.
Pup
[moderator's note: consecutive posts merged]

It would NOT change what PD can deliver. Same as with the USB charging specs the power delivery voltage is a wired negotiation between the master and slave(s) where there is a set of resistances presented by the slave device across the power wires when you plug it in. Something like either 10k, 4k or 2k as I recall. The master sees that and sets voltage output - up to 26vdc - and current limits accordingly. The regulators in the slaves of course need to be able to handle that so if no initial handshake resistance is seen by the master the port limits output to the standard 5vdc @ 1A.

That out of the way, a USB-C PD port can both deliver power and handle data -- it's just that data has to come from/go to a different master (for data) device port. In the case of say a laptop powered USB-C hub that is sized to power the laptop (up to 100w) the hub is the master for PD while the laptop is the master for all data. One cable between the laptop and powered hub handles both and the hub then splits off or passes through the (data only) to whatever is plugged into its ports.