Quote from: mikeywith on July 02, 2023, 02:15:46 PM

Room size is 10m*6m*3m / 32ft*19ft*9.8ft.

Each 60k btu AC pulls about 6kw worth of power, basically 1/3 of the miner's power.

If noise is a problem for the outside, how about heat? You'll be burning 175 + 60 = 235 kW. That's the equivalent of 20 of those things on full power:

(image source)

Anyone walking by may be in for a surprise.

Quote from: mikeywith on July 02, 2023, 10:43:46 PM

Based on that (assuming it's correct) if the outside temp in the above example was 15c, then I would need less cooling, simply put, I don't need the mining room to be at 15c, I am okay with 30c, which means probably using half the 10,236 cooling BTU will be enough to keep the room at 30c while the outside temp is 15c.

That would mean the other half of the heat has to flow through the walls. I'm not used to using BTUs, so I'd just keep everything in W. You produce 175kW, and have to remove 175kW. The efficiency (COP) of the airco will go up if the outside temperature is lower. Usually the COP is around 3-4, so when it's not too hot outside, you'll need 175/4kW for your airco. If it's hot outside, you'll need 175/3kW. That keeps the math much easier than bringing in BTUs.

Note that I have no practical experience whatsoever with running miners.