Quote from: unpluggedcoin on Today at 04:46:17 PM

Quote from: digaran on August 14, 2023, 03:42:47 PM

Here is another idea, lets see if it can be done or has any merits to it.

If we know the exact start and end range of a public key, we could divide the end range by a number to reduce it down as much as possible, maybe making it a 6 digits number, now we only have to change our 6 digit number and multiply it by the number which we first divided our end range with, we need to change the numbers in a way that it never goes beyond our end range when multiplied.

Now, before doing that, we need to add and subtract 1 G to our target and divide the results by 2, e.g. if our target is 256, we add 1, 2, 3, 4 etc and divide them all by 2 also we will add n/2 to all the results just to be safe and keep all of the keys to compare with our multiplication result. Eventually if we change our nonce, ( 6 digit number ) enough times and multiply it with powers of 2, 3 etc somewhere we should see a known key.

A simple example :

Start range 1, end range 512, our target is 95, now we divide 512 by 32 to get 16.

But first lets generate some offsets for our target.

Add 1 to 95 = 96/2 = 48
Add 3 to 95 = 98/2 = 49
Add 5 to 95 = 100/2 = 50
Sub 1 from 95 = 94/2 = 47
Sub 15 from 95 = 80/2 = 40

Now we have 48, 49, 50, 47 and 40, then we multiply 16 by 2, 3, 4, 5, 6, 7, etc until we see one of the keys above.

Imagine if we generate different offsets, like billions of them, then we could simply keep multiplying to find one of our targets.

This just came to my mind today, it's not cooked well , yet!😉

I already tried and test it and much more that I don't remember but when someone refer it I already know how it will slap our ass Grin

!
The reason this and every similar approach won't work is strictly due to the modular behaviour of calculations!
Which is why BSGS Kangaroo has thus far been the best approach which is increasing the chances of luck and meet at middle! However, any other way around addition and subtraction would not work trust me, BECAUSE there is no full stop, when your calculations go pass around the curve and completes a circle, it actually passes your assumed mark,, funny thing is IT WON'T RING A BELL OR SHOW ANY ALERT!!!!!!!! It would still be showing you the point and you'll be happy assuming it as per your assumption but it would change itself from being ODD to EVEN, thats where everyone go nuts when things don't work as per assumptions, elliptically speaking LOL!!
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hi brother, if you are a newbie here,, and you just have that idea today come to your mind, just put in your mind something, there is a lot of professional users here, we did think of all possibilities, dont you think that we already think of your idea ? of course we did think of a lot , do you have the right materiel hardware to do that Huh

if you do than ok we are with you lmao, its impossible to do it bro