Quote from: seoincorporation on Today at 03:21:19 PM

You can do it step by step:

c3b7c35f28c8a6089657b848366fb2e0a48d35e36b2184ef0dff520e217cad3c
cb7baee72882261268c582ebfcfee7e1cfbd166f8de3ff2182a11228d9d98217

Since both start with c, you can delete hex number:

3b7c35f28c8a6089657b848366fb2e0a48d35e36b2184ef0dff520e217cad3c
b7baee72882261268c582ebfcfee7e1cfbd166f8de3ff2182a11228d9d98217

Then change from Hex to Dec:

1681619964631834736909946030163359158422230413764693755437230999161102183740
5193970659261724958599847728180916496757916366088491570780608325158056854039

then rest them and that's all your possible combinations in that range:

3512350694629890221689901698017557338335685952323797815343377325996954670299

I hope this information helps, and if you are looking for a private key in that range i have to say it's impossible, they are too many digits to brute force.

Are you sure that form example there is 10^75 combinations, it seems like a lot Huh

, since all BTC priv. keys - 10^77?
No i dont wont to brute force it, that i know its impossible, juts curious.