Quote from: tmar777 on Today at 02:55:32 PM

Quote from: digaran on December 19, 2023, 01:54:12 PM

Quote from: yellowstripes on December 19, 2023, 06:13:22 AM

What 3rd key? Digaran ...please if you don't understand what I posted then ask...and nicely too for that matter. Just because our ideas and methods do not align does not mean yours is superior. And certainly put me in touch with the creator of the puzzle...I'll certainly tell him the first 4 digits of the private key of puzzle 130 for that 1 bitcoin and even gave a 110 bit range for it.

Puzzle 130 = first key. End range = second key. Their difference = third key. Maybe you should read your post again. Here is the deal, I will give you a public key, just tell me the first character of it's private key, you have 14 characters to choose from but only 1 correct guess. If you can't, then we'll have nothing to discuss on this subject.

Code:

022d410abfc76bc647c29819c3349c8a59c84af25feedf59b932643d10299660f0

Edit, I tried looking in my pockets, but couldn't find the creator of this puzzle, let me check the closet. Lol. If you want to get in touch, solve a puzzle, they will find you, don't worry about the time.😉

Can you explain the logic of the difference of a key by the end of the range etc? I cannot see any valid argument in this.

No one can do this. And Digaran won't be able to.
I will try to explain what the asymmetric encryption algorithm secp128k1 means. And why, you will never find the relationship by the beginning or ending bytes, between the private and public key. For example:
1. I wished for 2 factors and tell you the remainder of the modulo division.
Can someone tell me what numbers I multiplied? No he can’t!!!
If he can, it means he broke EC
2. This operation of multiplication and division modulo is performed 130 times in this case.
3. There is only linearity in modulo multiplication and division operations.
Well, let's start breaking the EC? I guessed two factors, the result of division modulo _P is equal to:

Code:

0x9478230a3fb794b615ac8f97768ab8feb86784804ef03de53ec26f8cbfbc37f5

Digaran please tell me the multipliers, I 2 multipliers. Or anyone. Grin