Quote from: mcdouglasx on Today at 09:34:42 PM

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Quote from: mabdlmonem on Today at 05:06:05 PM

Anyone know how to get the private key for 58.5?

Code:

import bitcoin

target= 585

Div=10

N=115792089237316195423570985008687907852837564279074904382605163141518161494337

a=bitcoin.inv(Div,N)

b= target*a % N

print("target r:",target/Div)
print("pk:",b)

58.5

PK 0.5
57896044618658097711785492504343953926418782139537452191302581570759080747169

pk 58
58

58.5
57896044618658097711785492504343953926418782139537452191302581570759080747169
+
58
=
57896044618658097711785492504343953926418782139537452191302581570759080747227

in hex
0x7fffffffffffffffffffffffffffffff5d576e7357a4501ddfe92f46681b20db

What about 58.51?)

5851/100

Code:

import bitcoin

target= 5851

Div=100

N=115792089237316195423570985008687907852837564279074904382605163141518161494337

a=bitcoin.inv(Div,N)

b= target*a % N

print("target r:",target/Div)
print("pk:",b)

If your script giving you result, then ok, other word, it's simple solutions, for play with every floating points, I am not at laptop at this time, later explain if your script not working...