i do some Experiment, trial and error for 66 bit
Let's say i take one 66 bit address for practice
000000000000000000000000000000000000000000000002be7989dd1a1a63ad | Hash 160 20cb77af1a425c5e74483d9b30cf950911a090de | 13zQNJwpREZogcPSkNJmYQzZ9HZQZS48Hx [TARGET]
result scan :
000000000000000000000000000000000000000000000002b809677889fb1078 | Hash 160 20cb78b594b77cf97259be5cc414f0a49f1bde81 | 13zQNb5x4P7vCjag18rZKCVHkBcqtddaLS | 102.92 sec | 136.0 keys/sec |
00000000000000000000000000000000000000000000000285a7e79fd01fc2a4 | Hash 160 20cbc445f68147eb89314c6710de2a7c5fc2e0fb | 13zQj6btR6awFjac835xsvDqeCtVyioiiW | 112.67 sec | 124.9 keys/sec |
000000000000000000000000000000000000000000000002757de2916bb72c92 | Hash 160 20cbc889d5186984e2189dd818e67d990f992459 | 13zQkFk3v2WXrhLVVhP2NKM1JT4Gbd6VoY | 153.39 sec | 110.4 keys/sec |
000000000000000000000000000000000000000000000002a6bdd8aaca2a5a56 | Hash 160 20cbb6398c3a2a9ad13eec60d2ffd84ed113d96d | 13zQfHTEd9EZncjXmiKMoZV7SqSZP39myL | 159.93 sec | 100.8 keys/sec |
I'm very grateful the result seem make some chance to hit the targeted and correct key
000000000000000000000000000000000000000000000002b809677889fb1078 | Hash 160 20cb78b594b77cf97259be5cc414f0a49f1bde81 | 13zQNb5x4P7vCjag18rZKCVHkBcqtddaLS | 102.92 sec | 136.0 keys/sec |
i make some checkpoint rules and check if at least 10 addresses have similarity in hash160 derived from private key.
What result are you talking about? I'm sorry if I can't see the wood for the trees, but I see absolutely nothing here that can be helpful in any way that relates to the topic of finding the puzzle. I see you have defined a target and I see you have listed four private keys and the corresponding addresses. There is no relation between them, how could there be, it wouldn't make any sense.
So what exactly did you find out or what makes you think that you're on the right track? Please don't misunderstand me, but I only see random data here without any relation to anything.
Did you know the work of bitcoin address, my codes to search the puzzle to sink the large private key range bro, random data ? it's calculated, the private key generate public key, and hash160 was from public key of address, the "20cb78" of hash 160 from 13zQNfHTEd9EZncjXmiKMoZV7SqSZP39myL is on range "2a6bdd8aaca2a5a56".
hash 160 of 13zQNJwpREZogcPSkNJmYQzZ9HZQZS48Hx is "20cb77af1a425c5e74483d9b30cf950911a090de", take a look "20cb78" and "20cb77" It doesn't look that far away from the hash160 generated from the private key.
if you change the 78 into 78 it make lot of changes on address.
20cb77af1a425c5e74483d9b30cf950911a090de : 13zQN
JwpREZogcPSkNJmYQzZ9HZQZS48Hx20cb78af1a425c5e74483d9b30cf950911a090de : 13zQN
agqxpgJMoqzrF3SUvYVq82ENKem4Jthe technical i learn is from
https://learnmeabitcoin.com/technical/address, you change some number/alpahbet on hash160 it's generate the different Bitcoin Address, but in other ways, we don't know what coresponding private key from that changes.
so what i do is collision hash160, it's like match the private key range and end range, and change little bit of private key if there's similiarity.
i will preview it the codes, the most unique is i do puzzle 40 bit within 18 second with that codes, it's not completed by speed, but by math from collision hash160.