Quote from: BlackHatCoiner on March 21, 2024, 06:04:04 PM

-snip-

So in the end the exactly didn't matter and I guessed this was why after this:

Pr (3 block) = 1 - (Pr( ≤2 block) + Pr (>3 block))
I still got the same 0.06133 which is roughly same as the 0.06131

My python code, works in similar way as your c++

Quote from: Amphenomenon on March 20, 2024, 01:06:24 PM

I wrote mine as a code in python, to be Frank my code is not professional _{i`m still working on that}

Code:

import math
Parameter = 1
RandomNumber = 3
EulerNumber = 2.71828

Probability = (Parameter ** RandomNumber ) * (EulerNumber ** (-Parameter)) / math.factorial(RandomNumber)
RoundedProbability = round(Probability, 4)
Inpercentage = str(RoundedProbability * 100)
print ('The chance of having exactly three blocks mined within the next 10 minutes = ',
RoundedProbability, 'or', Inpercentage + '%')

Poisson distribution was also spoken about on the bitcoin whitepaper in page 7 even in regards to your previous question

I did edit a part which was, math.factorial(3) to math.factorial(RandomNumber)