What has house edge to do with expected losses in a win/lose ratio??
The house edge determines the percentage of bets you will lose long-term.
For example, if the advertised house edge is 0,5%, then long-term you should lose 0,5% of your bets placed.
House edge will be accounted for wins and losses profit wise, not for the game outcome :: .
The chance for a win is only over 42% while the rest is accounted for losses or pushes. In other words, your calculation makes 0 sense.
When you claim the chance for win is only 42%, you claim that the house edge is 8%, right?
Because 50% minus chance to win 42% = 8% house edge!
But when you say the house edge is 8% and Stake says the house edge is only 0,5%, one of you is lying, right?
LOL, house edge doesn't determine how many bets you will lose, who told you this nonsense.
Basic math and statistic told me this.
When you make 200 bets at a 0,5% house edge, then you statistically will lose 1 bet, because 200 x 0,5% = 100% = 100% of 1bet.
For example, when you make 201 bets at 0,5% house edge, then statistically you will win 100 bets and lose 101 bets.
The 1 bet you statistically will lose more after 201 bets, that is the house edge.
If the house edge is 0% and you make 200 bets, then statistically you will win 100 bets and lose 100 bets = no bet more lost = no house edge.
For example, when you make 205 bets at 5% house edge, then statistically you will win 100 bets and lose 105 bets.
As everyone with a decent functioning brain can see,
the number of bets you statistically will lose more than you win is the house edge!