Quote from: JohnnyBitGoode on February 21, 2025, 09:43:25 AM

Hey fromport, I'm still confused about one thing.
If this label: https://www.dth.net/crypto/miners/lucky/lv08/LV08-PSU-label.jpg
de-rates the power supply to 60% of 180 watts (that's only 108 watts), how are you able to draw 164 watts from it?

Remember I said I felt I was pushing it by means of the PSU load?

If you think logically, the higher the input voltage, the power power you can get from the PSU to a max of 180watt

It will not be binary situation where the load can only be 60%
If the input AC voltage is between 176-264 volt you will get max output =180 watt
Let's assume that at lowest voltage = 85Volt AC input it can still to the 60% of the max power of 180 watt
I would assume the power scales from 85 volt (60%) to 176 volt (100%) and would be a linear line.
At the moment my input voltage is 122 Volt AC (measured with multimeter)
so from 176-85 Volt = 91 volt drop will result 40% loss of power.
176-122 volt = 54 volt drop, and it this would be a linear function it would be about a 24% loss of power
180 watts DC x 76% (24% loss) = 137 watt DC
We are talking about output power DC in the above calculations
The 164 watt I talked about is AC power measured of the input.
There is a thing called power factor on the AC side that might make the measured AC numbers higher than what they really are.
Complete new discussion.
Difference between AC power in and DC power output == efficiency of the PSU.